There are 3600 seconds in one hour.
120 seconds is 2 minutes
therefore, the fraction is
Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
.
Step-by-step explanation:
DC = 16 and
DB = 30 so
CB = 14
DB = 30 and
EB = 49 so
EB = 19
The heavy suitcase.
A small car would still weigh quite a lot, a tablet would weigh a lot less than that, and a watermelon is around 2kg (depends).
Since the "leading" runner in a race would be found in the first position, because he or she is in the lead, it means they are first, then I suppose I would find the "leading coefficient" in the first place in a polynomial as well.
