Answer:
3-hexanol
1 -butanol
2-pentanol
Explanation:
Let us recall that chromic acid or chromate are strong oxidizing agents. When they are oxidized, their colour changes from orange to green.
This shows a reduction in chromic acid or chromate. The reaction of chromic acid or chromate with a primary alcohol yields a carboxylic acid while reaction with a secondary substrate yields an alkanal.
Note that Tertiary alkyl halides are not be oxidized hence reactions involving a point where invitation carried along occur.
3-ethyl-3-pentanol is a tertiary alkyl halide hence it can not be oxidized.
All species are "(aq)" unless marked otherwise:
molecular: Na3PO4 + 3 AgNO3 → Ag3PO4(s) + 3 NaNO3
total ionic: 3 Na{+} + PO4{3-} + 3 Ag{+} + 3 NO3{-} → Ag3PO4(s) + 3 Na{+} + 3 NO3{-}
net ionic: PO4{3-} + 3 Ag{+} → Ag3PO4(s)
K2SO4(aq)+Na2CO3(aq) no reaction
molecular: Pb(NO3)2 + Na2CO3 → PbCO3(s) + 2 NaNO3
total ionic: Pb{2+} + 2 NO3{-} + 2 Na{+} + CO3{2-} → PbCO3(s) + 2 Na{+} + 2 NO3{-}
net ionic: Pb{2+} + CO3{2-} → PbCO3(s)
molecular: BaCl2 + 2 KOH → Ba(OH)2(s) + 2 KCl
total ionic: Ba{2+} + 2 Cl{-} + 2 K{+} + 2 OH{-} → Ba(OH)2(s) + 2 K{+} + 2 Cl{-}
net ionic: Ba{2+} + 2 OH{-} → Ba(OH)2(s)
The statement about the formation of the solar system that
are true and in a correct order are Gravitational force held the newly formed
planets around the sun; small planetary objects formed; hydrogen and helium
became concentrated in the outer solar system to form the outer planets. The answer
is letter D.
Calcium is Ca, Carbon is C, Chlorine is Cl
The answer is C
Answer is: molarity is 0,155 M.
V(solution) = 90,0 mL = 0,09 L.
ω(NaCl) = 0,92% ÷ 100% = 0,0092.
d(solution) = 1 g/mL.
m(solution) = V(solution) · d(solution).
m(solution) = 90 mL · 1 g/mL = 90 g.
m(NaCl) = 90 g · 0,0092 = 0,828 g.
n(NaCl) = 0,828 g ÷ 58,4 g/mol.
n(NaCl) = 0,014 mol.
c(solution) = 0,014 mol ÷ 0,09 L.
c(solution) = 0,155 mol/L.
