12 +1 C 6 How many protons, electrons, and neutrons are there

Which substance has the most thermal energy and will have the most heat flow from it?

Soloha48 [4]

Answer:

B. a nuclear reactor core (1000°C)......

7 0

3 years ago

Read 2 more answers

4. Can 200 ml of fluid be transferred to a 1-quart container? Explain the process that you used to arrive at your answer.

sukhopar [10]

Answer:

Yes, 200 ml of fluid can be transferred to a 1-quart container.

Explanation:

You must compare the two volumes, 200 ml and 1 quart. If 200 ml is less than or equal to 1 quart, then 200 ml of fluid can be transferred to a 1-quart container, else it is not possible.

To compare, the two volumes must be on the same system of units.

Quarts is a measure of volume equivalent to 1/4 of gallon.

One gallon is approximately 3.785 liters.

3.785 liter = 3.785 liter × 1,000 ml/liter

Then, to convert 1 quart to ml use the unit cancellation method:

(1/4)gallon × 3.785 liter/gallon × 1,000ml / liter = 946.25 ml

Thus, you get that a 1-quart container has volume of 946.25 ml, which allows that 200ml of fluid be transferred to it.

7 0

4 years ago

Li+1 had gained ______ one electron

zysi [14]

Maybe molecules one electron

3 0

3 years ago

Two parent reproduction involves cell division that includes ___________? *

Anettt [7]

Answer:

Mitosis

Explanation:

3 0

3 years ago

What mass of precipitate forms when 185.5 ml of 0.533 m naoh is added to 627 ml of a solution that contains 15.8 g of aluminum s

Law Incorporation [45]

Answer:

2,57 g of precipitate.

Explanation:

For the reaction:

6 NaOH + Al₂(SO₄)₃ → 2 Al(OH)₃ + 3 Na₂SO₄

The precipitate is Al(OH)₃.

185,5mL of 0,533M NaOH are:

0,1855L × 0,533M = 0,0989 moles NaOH

Moles of Al₂(SO₄)₃ are:

15,8g × $\frac{1mol}{342,15g}$ = 0,0462 moles Al₂(SO₄)₃

For the total reaction of 0,0989 moles NaOH with Al₂(SO₄)₃ you need:

0,0989moles NaOH × $\frac{1molAl_{2}(SO_{4})_{3}}{6 moles NaOH}$ = 0,0165 moles Al₂(SO₄)₃

As you have 0,0462 moles Al₂(SO₄)₃ the limiting reactant is NaOH.

0,0989 moles of NaOH produce:

0,0989moles NaOH × $\frac{2molAl(OH)_{3}}{6 moles NaOH}$ = 0,0330 moles of Al(OH)₃

These moles are:

0,0330 moles of Al(OH)₃ × (78 g/mol) = 2,57 g of Al(OH)₃ ≡ mass of precipitate

I hope it helps!

3 0

3 years ago

12 +1 C6How many protons, electrons, and neutrons are there