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Over [174]
2 years ago
14

A powerful missile reaches a speed of 5 kilometers per second in 10 seconds after its launch. What is the average acceleration o

f the missile during this period?
a) 0.2 meters/second^2
b) 0.4 centimeters/second^2
c) 0.5 meters/second^2
d) 0.5 kilometers/second^2
Physics
2 answers:
Aloiza [94]2 years ago
7 0
Average acceleration<span> is the change in velocity divided by an elapsed time.  So, we can calculate it as follows:

acceleration = 5 - 0 / 10 - 0 = 0.5 kilometers/second^2

Therefore the correct answer is option D.

Hope this answers the question. Have a nice day.</span>
AveGali [126]2 years ago
4 0

Average acceleration  =  (change in speed)  /  (time for the change)

The missile's change in speed is  (5,000 - 0)  =  5,000 m/s

Average acceleration  =  (5,000 m/s)  /  (10 sec)

                                 =      500 m/s²       (about  51 Gs)

Inconveniently, this isn't one of the choices on the list. Is there something wrong, either with the choices or with my solution ?

No. Relax. Everything is OK.

500 meters is the same thing as 0.5 kilometer.  So my answer can also be written as  0.5 km/s² .  That doesn't change anything, and it IS one of the listed choices.

The average acceleration is <em>0.5 km/sec²  (d)</em> .

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A stuntman with a mass of 80.5 kg swings across a moat from a rope that is 11.5 m. At the bottom of the swing the stuntman's spe
goldenfox [79]

Answer:

  • No
  • 5.49 m/s

Explanation:

The net force required to accelerate the stuntman in a circular arc of radius 11.5 m will be ...

  F = mv²/r . . . . where this m is the mass being accelerated, v is the tangential velocity, and r is the radius.

Here, the net force needs to be ...

  F = (80.5 kg)(8.45 m/s)²/(11.5 m) . . . . . where this m is meters

  ≈ 499.8175 kg·m/s² = 499.8 N

Gravity exerts a force on the stuntman of ...

  F = mg = (80.5 kg)(9.8 m/s²) = 788.9 kg·m/s² = 788.9 N

Then the tension required in the rope/vine is ...

  499.8 N+788.9 N= 1288.7 N

This is more than the capacity of the rope, so we do not expect the stuntman to make it across the moat.

_____

The allowed net force for centripetal acceleration is ...

  1000 N -788.9 N = 211.1 N

Then the allowed velocity is ...

  211.1 = 80.5v²/11.5

  30.16 = v² . . . .  multiply by 11.5/80.5

  5.49 = v . . . . . . take the square root

The maximum speed the stuntman can have is 5.49 m/s.

_____

<em>Comment on crossing the moat</em>

The kinetic energy at the bottom of the swing translates to potential energy at the end of the swing. At the lower speed, the stuntman cannot rise as high, so will traverse a shorter arc. At 8.45 m/s, the moat could be about 16.8 m wide; at 5.49 m/s, it can only be about 11.5 m wide.

5 0
3 years ago
Which of the following is a correct equation for total energy?
Liula [17]

Answer:

kinetic energy + potential energy

6 0
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When you and a friend move a couch to another room you exert a force of 75 N over 5m how much work will you do
sesenic [268]

The work done is 375 J

Explanation:

The work done by a force in moving an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this problem,

F = 75 N is the force applied to the couch

d = 5 m is the displacement

Assuming the force applied to the couch is parallel to the motion, \theta=0

And so, the work done is

W=(75)(5)(cos 0)=375 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

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6 0
3 years ago
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e-lub [12.9K]
The engineer built a device called a generator
4 0
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the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on
aleksandr82 [10.1K]

Answer:

your answer is here 180

Explanation:

900/2.5 * 2 = 180

6 0
2 years ago
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