Answer:
The maximum permissible propagation delay per flip flop stage is<u> 100 </u>n sec
Explanation:
1024 ripple counter has 10 J-K flip flops(210 = 1024).
So the total delay will be 10×x where x is the delay of each J-K flip flops.
The period of the clock pulse is 1× 10⁻⁶ s.
Now
10x <= 10⁻⁶ s
x <= 100 ns
x= 100 ns for prpoer operation.
pulse train with a frequency of 1 MHz is counted using a modulo-1024 ripple-counter built with J-K flip flops. For proper operation of the counter, the maximum permissible propagation delay per flip flop stage is <u>100 </u>n sec.
Answer:
42 m/s
Explanation:
by definition of the velocity(speed) of a wave,
The velocity of light, v, is the product of its wavelength, λ , and its frequency, f.
V= fλ
frequency - number of occurances in a unit time
(check the graph)
Very simple,Its all about calculating distance using the formula:
D = V x T
where,
V is the speed or velocity
D is distance
T is the time
In the given problem,there are two parts.
Lets do the calculations for both parts separately:
Part 1) Before the rain
Time = 130/95
= 1.37 hours <span> </span>
<span>Time taken after the rain = Total time - time taken before the rain </span>
<span> = 3.34 hours - 1.37 hours
= 1.97 hours </span>
<span>Distance covered after the rain = 1.97 hours x 65 km/h
= 128 km</span>
Hence,
<span>a) The total distance covered = 130 + 128
= 258 km
</span><span>b) Average speed = Total distance/Total time
= 260/3.34
= 78 km/h </span>
