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weqwewe [10]
3 years ago
6

Phosphorus bursts into flame when exposed to oxygen. What element might be used when storing pure phosphorus to keep it from rea

cting?
Physics
2 answers:
Mrrafil [7]3 years ago
5 0

Answer:

Noble gases. (Argon)

Explanation:

Noble gases are found in the group eight element on the periodic table and are known for their inert nature.

Meaning that they don't react easily with other elements.

Phosphorus is a reactive element that when exposed to air (oxygen) catches fire.

If phosphorus is stored under Noble gases escpecially Argon it won't react with the surrounding air in the laboratory.

bekas [8.4K]3 years ago
4 0
<h3><u>Answer;</u></h3>

Argon

<h3><u>Explanation;</u></h3>
  • Phosphorus is an element found in group 15 of the periodic table, it is one of the element that belongs to nitrogen family.
  • The element phosphorus exhibits allotrophy, namely; white phosphorus, red phosphorus and black phosphorus.
  • <u>Phosphorus, particularly the white phosphorus combines with oxygen so easily that it catches fire automatically. Thus, as a safety precaution, white phosphorus is stored under water in laboratories. </u>
  • <u>It may be also stored in argon, since argon is an inert element which belongs to the noble gases group.</u>

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Calculate the Poynting vector at the surface of the filament, associated with the static electric field producing the current an
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We anticipate a constant Poynting vector of magnitude since the hot resistor will be emitting heat and none of the electric or magnetic fields will change over time.

S = P/A

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1 year ago
To push a 26.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel
alukav5142 [94]

Answer:

(a) W = +397.1 J

(b) W = -204.6 J

(c) W = 0

(d) W= + 192.5 J

Explanation:

Work (W) is defined as the product of force (F) by the distance (d)the body travels due to this force. :

W= F*d Formula ( 1)

The forces that perform work on an object must be parallel to its displacement.

The forces perpendicular to the displacement of an object do not perform work on it.

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

Problem development

(a) Work performed by the worker's applied force on the box .

W= 209 N * 1.9 m = +397.1 J

(b) Work performed by the gravitational force on the crate

We calculate the weight component parallel to the displacement of the box:

We define the x-axis in the direction of the inclined plane ,25.0° to the horizontal.

We define the y-axis and in the direction of the plane perpendicular to the inclined plane.

W= m*g=26*9.8= 254.8N : total box weight

Wx= W*sen25.0°= 254.8*sen25.0°= 107.68 N

W = -Wx *d =107.68 N *1.9 m= -204.6 J

(c) Work performed by normal force (N) exerted by the incline on the crate

The force N is perpendicular to the displacement, then:

W=0

(d) Total work done on the crate

W = 397.1 J -204.6 J

W = 192.5 J

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Answer:

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