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ELEN [110]
3 years ago
13

Can you use scalars and vectors to describe a home run?

Physics
1 answer:
Svetach [21]3 years ago
8 0
The correct answer is Yes, you can !
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Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as muc
Musya8 [376]

Answer:

Second Choice.

Explanation:

Jack's Power = W/t

Jill's Power = 2W/(0.5)*t

2/0.5 = 4

Jill's Power = 4*W/t

Jill's Power is 4 times greater than Jack's

Second Choice

3 0
3 years ago
How strong is the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters
Brrunno [24]

Answer:

Match the scenario to the type of movement that caused it.

Ted is in his home when a strong vibration occurs that shakes the dishes out of his cupboards.

Whitney feels a slight tremor three weeks subsequent to an earthquake in a nearby town.

Sam pulls off the side of a road after feeling the road move unexpectedly while driving to work.

Foreshock

Mainshock

Aftershock

Explanation: PLZZ HELP ME I NEED TO PASS STEM!

6 0
3 years ago
Read 2 more answers
3. As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Vladimir [108]

Answer:

As an object’s temperature increases, the Rate at which it radiates energy increases.

7 0
3 years ago
Read 2 more answers
A tin can collapses if all air inside it is taken out why
Veseljchak [2.6K]

That only happens when the tin can is IN air.

In the familiar, comfy part of Earth's atmosphere where we live, the normal pressure of air is around 14.6 pounds on every square inch of everything. That's a big part of the reason why we're built with bodies that generate that same amount of pressure on the INSIDE pressing OUT. That way, we always have the same pressure pushing in both directions, so we know that we won't get crushed or blow up like balloons.

But we have to be careful with our bodies or other things when they're in places where the atmospheric pressure on the outside is NOT normal.

-- When a deep-sea diver goes hundreds of feet down in the ocean, and the pressure of the water is much GREATER than normal air.

-- When an astronaut has to go outside ... where there's NO air ... and fix something on the International Space Station.

When the pressure on the outside becomes very unusual, we have to wear special suits to protect our bodies from the unusual conditions.

The tin can in the story is a lot like our bodies. As long as it has air inside and air outside, the pressure is the same in both directions, so there's no particular force trying to deform the can. But ...

-- If you seal the can with the air inside it, take the can into a vacuum chamber, and pump the air out of the vacuum chamber, then the can only has pressure inside. It'll expand, and eventually spring a little hole in the metal, and all the air inside will blow out.

-- If you take all the air OUT of the can (so the can is REALLY 'empty'), then the pressure on it is all from the outside. In that situation, the can simply collapses, because there's nothing inside to provide pressure in the outward direction.

One more little thing to think about:

When you want some toothpaste to come drizzling out of the tube onto your brush, what do you do ? Do you perhaps squeeze the tube, and increase the pressure on the outside ?

4 0
3 years ago
The speed of an object and the direction in which it moves constitute a vector quantity known as the velocity. an ostrich is run
Orlov [11]
Velocity of an object is its rate of change of the object's position per interval of time. Velocity is a vector quantity which means that it consists of a magnitude and a direction. Magnitude is represented by the speed and the direction is represented by the angle. To determine the velocity components, we use trigonometric functions to determine the angle of the components. For the north component we, use the sine function while, for the west component, we use the cosine function. We calculate as follows:
north velocity component = (16.8 m/s) (sin 54°) = 16.4 m/s
<span>west velocity component = (16.8 m/s) (cos 54°) = 3.49 m/s</span>



6 0
4 years ago
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