<u>Answer:</u> The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.
<u>Explanation:</u>
Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized 
electrons are calculated by using the equation:
where,
n = 0 or any whole number
- Calculating the value of electrons for n = 0
Putting values in above equation, we get:
- Calculating the value of electrons for n = 1
Putting values in above equation, we get:
- Calculating the value of electrons for n = 2
Putting values in above equation, we get:
Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.
Answer:
41.16 moles of H2O
Explanation:
Ratio for the products-reactants is 1:6, so 1 mol of glucose is produced when plants use 6 moles of water.
Then, let's make a rule of three:
1 mol of glucose is produce by using 6 moles of water
6.86 moles of glucose are produced by the use of (6 . 6.86)/1 = 41.16 moles of H2O
The correct option in here is the first one: <span>pentane-1,5-diamine. This is also known as cadaverine. This is a common compund that produces that unpleasant odor from the fish. </span>
Answer:
"Gases and particles in Earth's atmosphere scatter sunlight in all directions. Blue light is scattered more than other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time."
Answer:
4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium
Explanation:
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:
- HCl: 2 moles
- Na: 1 mole
- NaCl: 2 moles
- H₂: 1 mole
You know the following masses of each element:
- H: 1 g/mole
- Cl: 35.45 g/mole
- Na: 23 g/mole
So, the molar mass of each compound participating in the reaction is:
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
- Na: 23 g/mole
- NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
- H₂: 2* 1 g/mole= 2 g/mole
Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- Na: 1 mole* 23 g/mole= 23 g
- NaCl: 2 moles* 58.45 g/mole= 116.9 g
- H₂: 1 mole* 2 g/mole= 2 g
So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?
mass of H₂= 4.8 g
<u><em>4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium</em></u>
