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EastWind [94]
3 years ago
7

An atom has 13 protons and 14 neutrons. What is its mass number?

Chemistry
2 answers:
Maslowich3 years ago
8 0

you add 13 and 14 and get 27 because It is the total amount.
Hitman42 [59]3 years ago
3 0
Protons have a mass of 1
Neutrons have a mass of 1

So 13*1 + 14*1 = Mass number 27
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The mass number of this atom is_________<br><br>​
galben [10]

Answer:

7

Explanation:

The mass number is neutrons plus protons

3 0
3 years ago
In the article "A Sea of Garbage" what message is each cartoon trying to convey to readers? Do they succeed?
sertanlavr [38]

Answer:

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8 0
3 years ago
Calculate the molar mass of carbon tetrafluoride (CF4) in grams per mole, rounding to proper significant figures, if mc= 12.01 u
Nata [24]

Answer:

molar mass of carbon tetrafluoride (CF4) is

(12.01 × 1 ) + ( 4 × 19.00)

= 12.01 + 76

= 88.01u

= 88u

Hope this helps

3 0
3 years ago
Read 2 more answers
. How many grams of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide? ____Cl
dlinn [17]

Answer: 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide.

Explanation:

The balanced chemical reaction is;

Cl_2+MgBr_2\rightarrow MgCl_2+Br_2

Cl_2 is the limiting reagent as it limits the formation of product and MgBr_2 is the excess reagent.

According to stoichiometry :

1 mole of Cl_2 produces = 1 mole of MgCl_2

Thus 2 moles of Cl_2 will produce=\frac{1}{1}\times 2=2moles  of MgCl_2

 Mass of MgCl_2=moles\times {\text {Molar mass}}=2moles\times 95g/mol=190g

Thus 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide

5 0
3 years ago
An analysis of a sugar compound is found to contain 132 grams of carbon (C), 22 grams of hydrogen (H), and 176 grams of oxygen (
ddd [48]
132 g of C  ,   22 g of H   , 176 g of O

132 + 22 + 176 => 330 g <span>of the substance

</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u        H = 1.0 u       O = 16.0 u

C = 132 / 12.0 => 11 moles

H = 22 / 1.0 => 22 moles

O = 176 / 16.0 => 11 moles

Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1

H = 22 / 11 => 2

O = 11 / 11 => 1

 formula empirically <span>is : CH</span>₂O

hope this helps!


8 0
3 years ago
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