Answer:
3Fe2O2---> Fe3O4
Explanation:
You need to add three to the left side to make it equal to the one on the right, and add a 2 since you can't change the subscripts
Explanation:
Selenium and tellurium are rare elements, respectively, in order of crustal abundance. However, polonium, on account of its radioactive decay, is less abundant. The main source of selenium and tellurium is the anode slime deposited during the electrolytic refining of copper.
The frequency of this photon is 5.94 x
.
Solution:
The speed of light has a value of approximately <u>3.00×108 m/s</u>
The wavelength should have units of meters.
The frequency should have units of Hz or s−1. Hz is hertz or reciprocal seconds.
We know the value of the speed of light and we are given the wavelength. All we have to do is rearrange the equation to solve for the frequency:
<u>v = c/λ</u>
= 3.00×
m/s/505×
m
= 5.94X
s-1
= <u>5.94X</u>
<u> Hz</u>
<u />
Frequency describes the number of waves passing through a particular location at a particular time. A class interval frequency is the number of observations that occur in a particular predefined interval. So, for example, if 20 of her ages 5-9 appear in the survey's data, the interval 5-9 has a frequency of 20. The class interval endpoints are the lowest and highest possible values of the variable.
Learn more about The frequency here:- brainly.com/question/254161
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Hello There!
The correct answer is B.
Hope This Helps You!
Good Luck :)
- Hannah ❤<span />
Explanation:
In an isotropic process, the equation is as follows.
![\frac{T_{2}}{T_{1}} = [\frac{P_{2}}{P_{1}}]^{\frac{k - 1}{k}}](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D%20%3D%20%5B%5Cfrac%7BP_%7B2%7D%7D%7BP_%7B1%7D%7D%5D%5E%7B%5Cfrac%7Bk%20-%201%7D%7Bk%7D%7D)
![T_{2} = T_{1} \times [\frac{P_{2}}{P_{1}}]^{\frac{k - 1}{k}}](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20T_%7B1%7D%20%5Ctimes%20%5B%5Cfrac%7BP_%7B2%7D%7D%7BP_%7B1%7D%7D%5D%5E%7B%5Cfrac%7Bk%20-%201%7D%7Bk%7D%7D)
As the given data is as follows.
= 500 K, m = 5 kg
= 5 bar,
= 1 bar
Now, putting the given values into the above formula as follows.
![T_{2} = T_{1} \times [\frac{P_{2}}{P_{1}}]^{\frac{k - 1}{k}}](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20T_%7B1%7D%20%5Ctimes%20%5B%5Cfrac%7BP_%7B2%7D%7D%7BP_%7B1%7D%7D%5D%5E%7B%5Cfrac%7Bk%20-%201%7D%7Bk%7D%7D)
= 315.7 K
As according to the ideal gas equation, PV = mRT
So, calculate the volume as follows.
V =
=
(as 1 bar = 10^{5} Pa[/tex])
= 
Now, we will calculate the value of
as follows.


= 
= 1.58 kg
Thus, we can conclude that the amount of mass remaining in the tank is 1.58 kg and its temperature is 315.7 K.