Y=-7/5x-3 as a proper fraction

Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a

EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, $\sin x$ and $\cos x$ are defined for all real numbers.

$\tan x=\frac{\sin x}{\cos (x)}$ , this function is not defined where $\cos x=0$ .

$\cot x=\frac{\cos x}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

$\csc x=\frac{1}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

For option A

The domain of $f(x)=\sin(x)$ is all real numbers.

The domain of g(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

For option B

The domain of $f(x)=\cos(x)$ is all real numbers.

The domain of f(x) =csc(x) is $x\ne n\pi$

For option C,

The domain of G(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

The domain of f(x) =cot(x) is $x\ne n\pi$

For option D;

The domain of f(x) =cot(x) is $x\ne n\pi$

The domain of f(x) =csc(x) is $x\ne n\pi$

3 0

3 years ago

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Hi! I need help on this, make sure to label each part with A,B,C, and D so I don’t type it in wrong. I will fine brainlist

ivolga24 [154]

Answer:

Step-by-step explanation:

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7 0

3 years ago

A rock is thrown upward from the top of a 112-foot high cliff overlooking the ocean at a speed of 96 feet per second. The rock's

Tasya [4]

The answerrrrrrrrrrrrrr is 256

3 0

3 years ago

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A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1

Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).