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MAXImum [283]
3 years ago
13

A mushroom gains its energy by decomposing the tissues of dead organisms. Should mushrooms be classified as autotrophs, heterotr

ophs, in both groups, or in neither group, and for what reason?
They are heterotrophs because their food is made by other organisms.

They are autotrophs because decomposition is very similar to photosynthesis.

They are both autotrophs and heterotrophs, because they may grow in sunlight or darkness.

They are autotrophs because they do not eat their food, as animals do.
Biology
1 answer:
stealth61 [152]3 years ago
4 0

Answer:

They are heterotrophs because their food is made by other organisms.

Explanation:

Unless the organism can create their food independently via photosynthesis or chemosynthesis, they must get their food from elswehere.

In the case of mushrooms, they are scavengers/decomposers, meaning they consume energy from once living organisms, thus classifying them as heterotrophs.

Have a nice day!

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2 years ago
Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based
zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values ​​can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

p^{2} = f(TLTL)

2pq = f(TSTL)

q^{2} = f(TSTS)

So, if the population is in balance:

P = p^{2}

H = 2pq

Q = q^{2}

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

f(TLTL) = P = p^{2} = 0,4^{2} = 0,16

f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48

f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36

I hope you have a SUPER day!

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