Answer:
24,19
Step-by-step explanation:
24+19=43
24-19=5
Answer:
10 boys
Step-by-step explanation:
6:2 simplfies to 3:1 30 / 3 = 10
30:10 simplfies down to 6:2
Answer:
(25,18) is the required solution.
Step-by-step explanation:
We are given the following in the question:
Let x be the number of trips to the airport and y represent the number of trips from the airport.
Total number of fares to and from the airport = 43
Thus, we can write the equation:

Price for a ride to the airport = $12
Price for a ride from the airport = $10
Total amount collected by the driver = $480
Thus, we can write the equation:

Solving the two equations, we get,

Thus, the driver made 25 trips to the airport and 18 trips from the airport.
The solution can be represented as (25,18)
Answer:
<em><u>see</u></em><em><u> </u></em><em><u>below</u></em><em><u>:</u></em><em><u>-</u></em>
Step-by-step explanation:

- Convert the mixed fractions into improper fractions.








Answer:
y-intercept: 10
concavity: function opens up
min/max: min
Step-by-step explanation:
1.) The definition of a y-intercept is what the resulting value of a function is when x is equal to 0.
Therefore, if the function's equation is given, to find y-intercept simply plug in 0 for the x-values:

y intercept ( f(0) )= 10
2.) In order to find concavity (whether a function opens up or down) of a quadratic function, you can simply find the sign associated with the x^2 value. Since 2x^2 is positive, the concavity is positive. This is basically possible, since it is identifying any reflections affecting the y-values / horizontal reflections.
3.) In order to find whether a quadratic function has a maximum or minimum, you can use the concavity of the function. The idea is that if the function opens downwards, the vertex would be at the very top, resulting in a maximum. If a function was open upwards, the vertex would be at the very bottom, meaning there is a minimum. Like the concavity, if the value associated with x^2 is positive, there is a minimum. If it is negative, there is a maximum. Since 2x^2 is positive, the function has a minimum.