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Ivahew [28]
3 years ago
15

1.What role did Enlightenment ideas play in the development of the United States? Give at least two examples to support your ans

wer.
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0
The Enlightenment had been one of the crucial parts of the American colonial America. The Enlightenment had influenced the concepts of freedom, government, and politics. oppression. Because of this, they were able to forge the foundation of the Modern America.
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Suppose the number of water lilies in pond doubles every day. If the pond was half covered on Monday, when was it only one-forth
Kaylis [27]

it would be covered by tuesday: because if it doubles each day and it is half full on monday it would be double that so it would be 100% 4/4 covered

6 0
3 years ago
Select from the drop-down menus to correctly complete each statement. −20>−21 −19>−20 −21 is located to the of −20 on a nu
LekaFEV [45]

Answer:

  left, right

Step-by-step explanation:

If you use the < or ≤ symbol to compare the numbers, their left-right order is the same as on the number line. Here, we would write the ordering as ...

  -21 < -20 < -19

So, we see that ...

  -21 is <em>left</em> of -20 on the number line

  -19 is <em>right</em> of -20 on the number line

4 0
3 years ago
Read 2 more answers
A circle has a radius of 3. An arc in this circle has a central angle of 20 degrees. What is the length of th arc?
dexar [7]

I got 1.047198m

hope this helps

7 0
3 years ago
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
(x*y=1210)=(-55=x+y)​
Romashka [77]
Evaluate
x⋅y, then set it equal to x+y.


X = y / y-1
8 0
3 years ago
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