First identify which is being oxidized and reduced. In this case, the Mg is being oxidized and the Hg is being reduced.
Mg --> Mg+2
<span>Hg+2 --> Hg+1
</span>
Then you have to balance each half reaction first with electrons before adding them together in one equation

⇒

and

⇒
and then combine them together to form

⇒

It isn't necessary to keep the electrons but its essential to know how many there are in order to know how many are in the equation in order to calculate the reaction energy. Note: A<span>dd H+ and H2O to balance the H's and O's in acidic solution if needed.</span>
Is there any choices or is this a fill in the blank question?
Answer:
P2= 125.26 Kpa
Explanation:
V1= 489.6 ml=0.4896L
V2= 750 ml= 0.750L
V1= 180 KPa= 180000 Pa
P2= ?
T1= 10 = 10 + 273.15 = 283.15K
T2= 28.7+273.15= 301.85K
180000Pa* 0.4896L/ 283.15K * 301.85K/0.75L
P2= 12526.28553
P2= 125.26 KPa
Answer:
no tengo la menor idea de que es
Answer: V= 366.3 L
Explanation:
Using the ideal gas law; PV = nRT
P= pressure = 101 kPa , n = Number of moles = 16.3 moles
V = Volume = ? R= Gas constant = 8.31 kPa L/Mol K
T= Temperature = 273K
We make ''V'' the subject of the formular;
V = n R T/ P = 16.3mol x 8.31 kPa. L / mol. K x 273 K
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101 kPa
V = 366.3 L