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Fynjy0 [20]
1 year ago
12

Find the mean of the data.

Chemistry
2 answers:
Nikitich [7]1 year ago
8 0

Answer:

please mark as brainliest

6 Is your mean

Explanation:

Mean = sum of numbers/how many numbers there are

So first,

2+9+4+7+8= 30

Now,

30/5 = 6

algol131 year ago
7 0
Adding them all together getting 30 and then dividing by the numbers used I got 6
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What state of matter has the most kinetic energy
kvv77 [185]

Answer: Gas

Explanation:

since the gas molecules arent being forcefully bonded together like a solid would be, and liquids tend to have lower kinetic energy than solids

3 0
3 years ago
The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
3 years ago
What is the element presented, in this compound?
DerKrebs [107]

compound name compound formula elements present

water H2O hydrogen (H) and oxygen (O)

ammonia NH3 nitrogen (N) and hydrogen (H)

carbon monoxide CO carbon (C) and oxygen (O)

carbon dioxide CO2 carbon (C) and oxygen (O)

4 0
3 years ago
Read 2 more answers
When can all the coefficients in a balanced equation represent volume ratios? when reactants and products are solids at stp when
Alexxx [7]

Answer: when reactants and products are gases at STP.


Justification:


1) STP stands for standard temperature (0°) and pressure (1 atm).


2) According to the kinetic molecular theory of the gases, and as per Avogadro's principle, equal volumes of gases, at the same temperature and pressure, have the same number of molecules.



3) Since the coefficients in a balanced chemical equation represent number of moles, when reactants and products are gases at the same temperature and pressure, the mole ratios are the same that the volume ratios, and then the coefficients of the chemical equation represent the volume ratios.


8 0
3 years ago
Read 2 more answers
Wind : swirls :: chemical bond : ___________.
drek231 [11]
Options are as follow,

1)  Flashes
2)  Skips
3)  Stretches
<span>4)  Jumps
</span>
Answer:
            Option-3 (stretches) is the correct answer.

Explanation:
                    The best analogy which suits a chemical bond is the stretching of chemical bonds. Remaining verbs doesn't explain the property of chemical bond. For example, the chemical bonds did not flashes, neither they skip or jump.
                    The chemical bonds can stretch and bend. As predicted from IR spectroscopy, different bonds can stretch and bend at different energies. The stretching of bonds require more energy while, bending of bonds require less energy.
4 0
4 years ago
Read 2 more answers
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