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Lena [83]
2 years ago
13

Help lol plsssss!!?!?

Mathematics
1 answer:
Marat540 [252]2 years ago
5 0

Answer:

3y-x =-6

Step-by-step explanation:

The equation of a line in point slope form is expressed as;

y-y0 = m(x-x0)

(x0, y0) is the point = (3, -1)

Given the equation 3xs+y = 1

Get the slope

y = -3x + 1

mx = -3x

m = -3

Since the equation needed is perpendicular to the line, the slope will be expressed as;

M = -1/-3

M = 1/3

Substitute and get the equation needed

y-y0 = m(x-x0)

y - (-1) = 1/3(x-3)

y+1 = 1/3(x-3)

3(y+1) = x-3

3y+3 = x-3

3y - x = -3-3

3y-x =-6

This gives the required equation

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3 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
100 <---- 2 zeros
Tom [10]
The number 100 -> that has 2 zeros
Is the same as 10^2 as for this simplified is equal to 100.
100=100
They are the same. They have the same number of zeros.
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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