Question

Help lol plsssss!!?!?

Answer 1

Answer:

3y-x =-6

Step-by-step explanation:

The equation of a line in point slope form is expressed as;

y-y0 = m(x-x0)

(x0, y0) is the point = (3, -1)

Given the equation 3xs+y = 1

Get the slope

y = -3x + 1

mx = -3x

m = -3

Since the equation needed is perpendicular to the line, the slope will be expressed as;

M = -1/-3

M = 1/3

Substitute and get the equation needed

y-y0 = m(x-x0)

y - (-1) = 1/3(x-3)

y+1 = 1/3(x-3)

3(y+1) = x-3

3y+3 = x-3

3y - x = -3-3

3y-x =-6

This gives the required equation