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Lena [83]
3 years ago
13

Help lol plsssss!!?!?

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

3y-x =-6

Step-by-step explanation:

The equation of a line in point slope form is expressed as;

y-y0 = m(x-x0)

(x0, y0) is the point = (3, -1)

Given the equation 3xs+y = 1

Get the slope

y = -3x + 1

mx = -3x

m = -3

Since the equation needed is perpendicular to the line, the slope will be expressed as;

M = -1/-3

M = 1/3

Substitute and get the equation needed

y-y0 = m(x-x0)

y - (-1) = 1/3(x-3)

y+1 = 1/3(x-3)

3(y+1) = x-3

3y+3 = x-3

3y - x = -3-3

3y-x =-6

This gives the required equation

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The body temperatures of adults are normally distributed with a mean of 98.6degrees° F and a standard deviation of 0.60degrees°
Schach [20]

Answer:

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 98.6, \sigma = 0.6, n = 36, s = \frac{0.6}{\sqrt{36}} = 0.1

If 36 adults are randomly​ selected, find the probability that their mean body temperature is greater than 98.4degrees° F.

This is 1 subtracted by the pvalue of Z when X = 98.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{98.4 - 98.6}{0.1}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

6 0
3 years ago
A baker recorded the number of batches of
azamat

Answer:

B. The lower extreme increased.

Step-by-step explanation:

From the original box and whisker plot, the lower extreme (minimum) is 5 ; The upper extreme, maximum is 15.

The number of batches baked on the eight day is 20. This exceeds tbe previous maximum value. Hence, upper extreme( maximum) value of the new plot will change from 15 to 20.

The lower extreme isn't affected as the obtained value isn't below 5.

The median value will Increase and the upper quartile value will also increase. Once the upper quartile value increases, the interquartile range will also increase

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60 meters
4 seconds

To find the unit rate, divide the distance by the time.

60/4=15meters per second= 15m/s
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where is the table ? I can't answer

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7 0
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