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Anni [7]
3 years ago
10

You can determine the concentration of acids or bases in a solution by using___________.

Chemistry
1 answer:
Doss [256]3 years ago
6 0
The answer is A. The Ph scale
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Rewrite each equation below with the delta H value included with either the reactants or the products and identify the reaction
yanalaym [24]
A) 2H₂(g) + O₂(g) → 2H₂O(l) + 285.83 kJ
Exothermic

B) 2Mg + O₂ → 2MgO + 1200kJ
Exothermic
5 0
3 years ago
Calculate the molarity (m) of a solution prepared by dissolving 10.7 g nai in 0.250 l.
Lilit [14]
Molarity is defined as the number of moles of solute in 1 L of solution 
number of moles of NaI - 10.7 g / 150 g/mol = 0.0713 mol 
there are 0.0713 mol in 0.250 L
we need to find the number of NaI moles in 1 L
if 0.250 L contains - 0.0713 mol 
then 1 L contains - 0.0713 mol / 0.250 L  = 0.285 mol/L
molarity is 0.285 M
7 0
4 years ago
Read 2 more answers
Advantages and disadvantages of chemical​
Anit [1.1K]

Answer:

Advantages :they are used for seeing chemical reactions .

they are used for doing chemical experiment .

they are used for making affective medicines .

Disadvantages :they harms to our environment.

they can make side effects in our body by affective medicines made by chemicals.

while doing different unknown experiments they make explosions which can also harm to us.

6 0
3 years ago
What is the pH if 1mL of 0.1M HCl is added to 99mL of pure water?
coldgirl [10]

Answer:

pH of buffer after addition of 1 mL of 0,1 M HCl = 7,0

Explanation:

It is possible to use Henderson–Hasselbalch equation to estimate pH in a buffer solution:

pH = pka + log₁₀

Where A⁻ is conjugate base and HA is conjugate acid

The equilibrium of phosphate buffer is:

H₂PO₄⁻ ⇄ HPO4²⁻ + H⁺    Kₐ₂ = 6,20x10⁻⁸; pka=7,2

Thus, Henderson–Hasselbalch equation for 7,00 phosphate buffer is:

7,0 = 7,2 + log₁₀ \frac{[HPO4^{2-}] }{[H2PO4^{-}]}

Ratio obtained is:

0,63 = \frac{[HPO4^{2-}] }{[H2PO4^{-}]}

As the problem said you can assume [H₂PO₄⁻] = 0,1 M and [HPO4²⁻] = 0,063M

As the amount added of HCl is 0,001 M the concentrations in equilibrium are:

H₂PO₄⁻   ⇄   HPO4²⁻ +        H⁺

0,1 M +x      0,063M -x  0,001M -x -<em>because the addition of H⁺ displaces the equilibrium to the left-</em>

Knowing the equation of equilibrium is:

K_{a} = \frac{[HPO_{4}^{2-}][H^{+}]}{[H_{2} PO_{4}^{-}]}

Replacing:

6,20x10⁻⁸ = \frac{[0,063-x][0,001-x]}{[0,1+x]}

You will obtain:

x² -0,064 x + 6,29938x10⁻⁵ = 0

Thus:

x = 0,063 → No physical sense

x = 0,00099990

Thus, [H⁺] in equilibrium is:

0,001 M - 0,00099990 = 1x10⁻⁷

Thus, pH of buffer after addition of 1 mL of 0,1 M HCl =

-log₁₀ [1x10⁻⁷] = 7,0

A buffer is a solution that can resist pH change upon the addition of an acidic or basic components. In this example you can see its effect!

I hope it helps!

5 0
3 years ago
How does the law of conservation of mass apply this reaction mg + HCl -- H2 + mgcl2
rjkz [21]

The correct answer is D hydrogen and chlorine need to be balanced there's an equal amount of magnesium on each side. I just took the test and got the correct answer.

7 0
3 years ago
Read 2 more answers
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