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3 years ago

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b

Mathematics

1 answer:

Dovator [93]3 years ago

7 0

Answer:

Step-by-step explanation:

∵A= l×b

⇒A= 4ab^2 × 6a^2b

⇒A= 24a^2b+1×b^2

Explanation: When multiplying indices, add the exponents of similar bases (that is, a^2×a = a^2+a^1 =a³) thus a^2b+1.

I hope this helped.

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3 years ago

A rectangle and a square have the same area. The length of the rectangle is seventy feet more than two times its width. The leng

Zanzabum

Using the side of the square find the area:

Area = 30^2 = 900 square feet.

The rectangles area is the same, 900 square feet.

Let the width = X

The length would be 2X + 70

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3 years ago

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b￼￼

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b