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3 years ago

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b

Mathematics

1 answer:

Dovator [93]3 years ago

7 0

Answer:

Step-by-step explanation:

∵A= l×b

⇒A= 4ab^2 × 6a^2b

⇒A= 24a^2b+1×b^2

Explanation: When multiplying indices, add the exponents of similar bases (that is, a^2×a = a^2+a^1 =a³) thus a^2b+1.

I hope this helped.

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Select the simplification that accurately explains the following statement.

lutik1710 [3]

Answer:

Option (b) is correct.

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2$

Step-by-step explanation:

Given: $(2^\frac{1}{4} )^4$

We have too choose the correct simplification for the given statement.

Consider $(2^\frac{1}{4} )^4$

Using property of exponents, $(a^m)^n=a^m\times a^m\times a^m\times ....\times (n\ times)$

We have,

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}$

Again applying property of exponents $a^m\times a^m=a^{n+m}$

We have,

$(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}$

Simplify, we have,

$(2^\frac{1}{4} )^4=2^{\frac{4}{4}}$

we get,

$(2^\frac{1}{4} )^4=2^{1}=2$

Thus, $(2^\frac{1}{4} )^4=2$

Option (b) is correct.

8 0

3 years ago

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Identify an equation in slope-intercept form for the line parallel to y = -3x + 7

melisa1 [442]

Correct Answer is B!!!

4 0

3 years ago

Can someone help me pls

JulsSmile [24]

Answer:

Step-by-step explanation:

horizontal distance = cos(28)*120

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3 years ago

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den301095 [7]

Answer:

46790

Step-by-step explanation:

3 0

2 years ago

If an area of a rectangle with width x can be represented with the expression A(x)=x(14-x), what is the perimeter of the rectang

AlekseyPX

To solve for the perimeter first figure out the length and width from the formula of area for the rectangle
A = LxW
A = (14-X)•X
L = (14-X)
W = X
P = 2L + 2W
P = 2(14-X) + 2(X)
P = 28 - 2X + 2X
P = 28.
The perimeter of the rectangle is A. 28.

6 0

3 years ago

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b￼￼

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b