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2 years ago

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b

Mathematics

1 answer:

Dovator [93]2 years ago

7 0

Answer:

Step-by-step explanation:

∵A= l×b

⇒A= 4ab^2 × 6a^2b

⇒A= 24a^2b+1×b^2

Explanation: When multiplying indices, add the exponents of similar bases (that is, a^2×a = a^2+a^1 =a³) thus a^2b+1.

I hope this helped.

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FromTheMoon [43]

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3 years ago

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Which set of angles could be the interior angles of a triangle? O A. 10° 20°, and 60° B. 20°. 20°, and 50° C. 209.30'. and 50° D

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2 years ago

Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides. The area of EFGH is 35 square units. What i

sasho [114]

*see attachment for the figure described

Answer:

5 units

Step-by-step explanation:

==>Given the figure attached below, let where FH and EG intercepted be K.

Since FH are midpoints of parallel lines, KE = KG = x.

Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.

Area of kite = ½ × d1 × d2

Where d1 = KH = 7

d2 = EG = KE + KG = x + x = 2x

Area of kite EFGH = 35

THUS:

35 = ½ × 7 × 2x

35 = 1 × 7 × x

35 = 7x

Divide both sides by 7

35/7 = x

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2 years ago

Find the value of this expression if x=-1 and y=-5 x^2y/4

REY [17]

Answer:

$\large\boxed{-\dfrac{5}{4}=-1\dfrac{1}{4}}$

Step-by-step explanation:

$\text{Put the values of x = -1 and y = -5 to the expression}\ \dfrac{x^2y}{4}:\\\\\dfrac{(-1)^2(-5)}{4}=\dfrac{(1)(-5)}{4}=\dfrac{-5}{4}$

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2 years ago

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b￼￼

Find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b