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3 years ago

Find the equation of the line parallel to y = 2/3-7 (2 over 3) passing through A(6,-1).

Mathematics

1 answer:

wariber [46]3 years ago

8 0

Answer:

y = 2/3x - 5

Step-by-step explanation:

y = 2/3x + b

-1 = 2/3(6) + b

-1 = 4 + b

-5 = b

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Help pls yall i will give brainliest

miskamm [114]

Answer:

Y=3x+2, Y= -3x-2

Step-by-step explanation:

If you need a consistent (parallel) line you must have very similar equations, with only positives and negatives being changed. If it's Y=3x+2, only the 2 is changed from negative to positive changing the lines position. If it's Y= -3x-2 then the X value is moved to a different coordinate and the -2 keeps the change.

Hope this helps and please critique what I've done if im wrong.

6 0

3 years ago

Find the exact area of each shaded region

Anton [14]

$\bf \textit{area of a circular ring}\\\\ A=\pi (R^2-r^2)~~ \begin{cases} R=larger\\ \qquad radius\\ r=smaller\\ \qquad radius\\[-0.5em] \hrulefill\\ R=12\\ r=7 \end{cases}\implies A=\pi (12^2-7^2) \implies A=95\pi$

5 0

3 years ago

What is the equation of the line that passes through the points (–2, 2) and (0, 5)?

lana66690 [7]

Answer:

The equation of line is given by

$y=\frac{3}{2}x+5$

Step-by-step explanation:

We have been given the points (–2, 2) and (0, 5) and we have to find the equation of the line.

Let us first find the slope of the line using the formula

$m=\frac{y_2-y_1}{x_2-x_2}$

On substituting the values, we get

$m=\frac{5-2}{0+2}$

$m=\frac{3}{2}$

Now, using the point slope form, the equation of line is given by

$y-y_1=m(x-x_1)\\y-2=\frac{3}{2} (x+2)\\\\y-2=\frac{3}{2}x+3\\\\y=\frac{3}{2}x+5$

Therefore, the equation of line is given by

$y=\frac{3}{2}x+5$

6 0

4 years ago

Read 2 more answers

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean $\mu$ and standard deviation $\sigma$ , we have these following probabilities

$Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827$

$Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545$

$Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973$

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So $\mu = 53, \sigma = 11$

So:

$Pr(53-11 \leq X \leq 53+11) = 0.6827$

$Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545$

$Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973$

-----------

$Pr(42 \leq X \leq 64) = 0.6827$

$Pr(31 \leq X \leq 75) = 0.9545$

$Pr(20 \leq X \leq 86) = 0.9973$

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have $Pr(31 \leq X \leq 75) = 0.9545 = 0.9545$ subtracted by $Pr(42 \leq X \leq 64) = 0.6827$ is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

$P = {0.9545 - 0.6827}{2} = 0.1359$

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0

4 years ago

Question 3 of 13 Which represents the explicit formula for the arithmetic sequence a n = 15 + 5 ( n − 1 ) a n = 15 + 5 n - 1 in

tatyana61 [14]

Answer:

$\textbf{Option C: \mathmode{\mathit{f(n) = 5n + 10}}}\\$

Step-by-step explanation:

$\textrm{There are two simple ways to solve the equation:}\\{\underline{\textbf{Method I:}}\hspace{3mm} \textup{\textrm{ Substitute \mathmode{n = 1} in the equation{\mathit{a} = 15 + 5(n - 1)}}}}\\\textup{\textrm{i.e., \mathrm{a = 15 + 5(0) = 15}}}\\\\$

$\textup{\textrm{In the options, again substitute \mathbf{n = 1}.}}\\\textup{\textrm{We can easily see that only Option \mathbf{C} satisfies the equation and renders 15. }}\\\textup{\textrm{Now for \textbf{\underline{Method II:}}\textup{\textrm{Simplify the given equation into \mathit{a = 15 + 5n - 5}}}}}\\\implies \textup{\textrm{a = 5n + 10}}\\$

3 0

3 years ago