Use your rules of logs. First the sum of two logs with same base is the product of the parts. Log7 (5x) = log7 60. Now since both sides have same log and base the parts are equal. 5x = 60. Divide by 5 to get a result of x = 12
Answer:
Step-by-step explanation:
um
The distance between him and school is 1.59 miles. Of course this distance is linear to make this problem simple. He walks with a speed of 3 miles per hour or 0.00083 mile per second.
To calculate time from distance and speed we use this formula:
seconds. To convert minutes we divide number of second by 60.
.
It will take him approximately 60 minutes to get to school.
<h3>Question:</h3>
The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x.
<h3>To find:</h3>
<h3>Given:</h3>
<h3>Answer :</h3>
<u>To</u><u> </u><u>find</u><u> </u><u> </u><u>area</u><u> </u><u>first</u><u> </u><u> </u><u>we</u><u> </u><u>should</u><u> </u><u>know</u><u> </u><u> </u><u>value</u><u> </u><u> </u><u>of</u><u> </u><u>with</u><u>.</u>
So first Let's find width by using this formula:
![\blue{\boxed { \sf \underline {Perimeter=2(Length+Width)}}}](https://tex.z-dn.net/?f=%5Cblue%7B%5Cboxed%20%7B%20%5Csf%20%5Cunderline%20%7BPerimeter%3D2%28Length%2BWidth%29%7D%7D%7D)
Insert Value of length and perimeter.
![: \implies \sf 30 = 2(x + width)](https://tex.z-dn.net/?f=%20%3A%20%20%5Cimplies%20%5Csf%2030%20%3D%202%28x%20%2B%20width%29)
![: \implies \sf \dfrac{30}{2} = (x + width)](https://tex.z-dn.net/?f=%20%3A%20%20%5Cimplies%20%5Csf%20%20%5Cdfrac%7B30%7D%7B2%7D%20%3D%20%28x%20%2B%20width%29)
![: \implies \sf{}x + width = \dfrac{ { \cancel{30}}^{ \: 15} }{ { \cancel{2}}^{ \: 1} }](https://tex.z-dn.net/?f=%20%20%3A%20%20%5Cimplies%20%5Csf%7B%7Dx%20%2B%20width%20%3D%20%20%5Cdfrac%7B%20%7B%20%5Ccancel%7B30%7D%7D%5E%7B%20%5C%3A%2015%7D%20%7D%7B%20%7B%20%5Ccancel%7B2%7D%7D%5E%7B%20%5C%3A%201%7D%20%7D%20)
![: \implies \sf{}x + width = 15](https://tex.z-dn.net/?f=%20%20%3A%20%20%5Cimplies%20%5Csf%7B%7Dx%20%2B%20width%20%3D%2015)
![: \implies \sf{} \star \underline{\underline{ width = 15 - x}} \star](https://tex.z-dn.net/?f=%20%20%3A%20%20%5Cimplies%20%5Csf%7B%7D%20%20%5Cstar%20%5Cunderline%7B%5Cunderline%7B%20width%20%3D%2015%20-%20x%7D%7D%20%5Cstar)
Now Let's find Area by using this formula
![\blue{\boxed { \sf \underline {Area=Length \times Width }}}](https://tex.z-dn.net/?f=%5Cblue%7B%5Cboxed%20%7B%20%5Csf%20%5Cunderline%20%7BArea%3DLength%20%5Ctimes%20Width%20%7D%7D%7D)
![: \implies \sf{}Area = x \times (15 - x)](https://tex.z-dn.net/?f=%3A%20%5Cimplies%20%5Csf%7B%7DArea%20%3D%20x%20%5Ctimes%20%2815%20-%20x%29)
![: \implies \sf{} \star \underline{\underline{ Area = 15x - {x}^{2} \: cm {}^{2} }} \star](https://tex.z-dn.net/?f=%20%20%3A%20%20%5Cimplies%20%5Csf%7B%7D%20%20%5Cstar%20%5Cunderline%7B%5Cunderline%7B%20Area%20%3D%2015x%20-%20%20%7Bx%7D%5E%7B2%7D%20%20%5C%3A%20cm%20%7B%7D%5E%7B2%7D%20%7D%7D%20%5Cstar)
hope it helps!