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klasskru [66]
3 years ago
5

The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x. step by step explanation.​

Mathematics
1 answer:
Debora [2.8K]3 years ago
3 0
<h3>Question:</h3>

The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x.

<h3>To find:</h3>

  • Area in terms of x

<h3>Given:</h3>

  • Perimeter = 30 cm

  • L = x

<h3>Answer :</h3>

<u>To</u><u> </u><u>find</u><u> </u><u> </u><u>area</u><u> </u><u>first</u><u> </u><u> </u><u>we</u><u> </u><u>should</u><u> </u><u>know</u><u> </u><u> </u><u>value</u><u> </u><u> </u><u>of</u><u> </u><u>with</u><u>.</u>

So first Let's find width by using this formula:

\blue{\boxed { \sf \underline {Perimeter=2(Length+Width)}}}

Insert Value of length and perimeter.

:  \implies \sf 30 = 2(x + width)

:  \implies \sf  \dfrac{30}{2} = (x + width)

:  \implies \sf{}x + width =  \dfrac{ { \cancel{30}}^{ \: 15} }{ { \cancel{2}}^{ \: 1} }

:  \implies \sf{}x + width = 15

:  \implies \sf{}  \star \underline{\underline{ width = 15 - x}} \star

Now Let's find Area by using this formula

\blue{\boxed { \sf \underline {Area=Length \times Width }}}

: \implies \sf{}Area = x \times (15 - x)

:  \implies \sf{}  \star \underline{\underline{ Area = 15x -  {x}^{2}  \: cm {}^{2} }} \star

hope it helps!

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