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blondinia [14]
3 years ago
8

Type 700 words in 10 min how many words per min

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:5.4

Step-by-step explanation:

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Can Someone Help Me Simplify These Expressions
Citrus2011 [14]
-2k - (-7)k
= -2k + 7k
= 5k

-7(p + 2) + 9(p - 4)
= -7p - 14 + 9p - 36
= 2p - 50

7 0
3 years ago
jonah earned $5 more than half of karen’s salary, k. which of the following expressions represents jonahs earnings
MrMuchimi

Answer: one half(k + 5)

one halfk + 5

one half + k + 5

one halfk > 5

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Which is a correct first step in solving the inequality –4(2x – 1) > 5 – 3x?
oksian1 [2.3K]

The first step in solving the inequality is to distribute –4 to get -8x + 4 > 5 - 3x

<em><u>Solution:</u></em>

Given inequality is:

-4(2x - 1) > 5 - 3x

The first step in solving the inequality is to distribute -4 to terms inside the bracket in left side of equation

This is done according to BODMAS rule

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Thus in given inequality, brackets has to solved first

This is done by using distributive property

a(b + c) = ab + bc

Therefore,

-4(2x - 1) = (-4 \times 2x) +(-4 \times -1) = -8x + 4

Thus, the inequality becomes,

-4(2x - 1) > 5 - 3x\\\\-8x + 4>5-3x\\\\-5x>1\\\\x

Thus solution to given inequality is found

6 0
4 years ago
Determine which postulate or theorem can be used to prove that LMN NOL
balu736 [363]
Sss similarity theorem
3 0
3 years ago
Read 2 more answers
BRAINLIESTT ASAP! PLEASE HELP ME :)
sweet [91]

\displaystyle y = Atan(Bx - C) + D

According to this <em>trigonometric function</em>, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{π}{B} \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical</em><em> </em><em>shift</em><em> </em>might tell you to extend the troughs on each end of your graphs, beyond the <em>midline</em>.

* All tangent functions have NO AMPLITUDES.

I am joyous to assist you anytime.

6 0
3 years ago
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