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Debora [2.8K]
3 years ago
7

In what part of the plant is glucose suger made?​

Physics
1 answer:
Eduardwww [97]3 years ago
5 0

\large  \mid   \underline {\bf {{{\color{navy}{Leaf  \:  \:  \: Chloroplast \: ...}}}}} \mid

<h2>☛ More Information :</h2>

  • Green plants manufacture glucose through a process that requires light, known as photosynthesis.

  • Glucose is stored in the form of starch in plants.
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Ugo [173]

Answer:

Given x = bt-c²

We know that t= time (s)

x= distance (m)

So

bxt= meters

m/s x s= m

And then c= m/s²

And b= m/s

6 0
3 years ago
Which type of box will best protect a fragile object by minimizing the force on the object
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There is not picture or anything what are the answer choices?
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3 years ago
A holiday ornament in the shape of a hollow sphere with mass M = 1.50×10−2 kg and radius R = 5.50×10−2 m is hung from a tree lim
pickupchik [31]

Answer:

T = 0.607 seconds

Explanation:

Given:

Mass, M = 1.50 × 10⁻² kg

Radius, R = 5.50 × 10⁻² m

Now,

the time period in terms of moment of inertia is given as:

T = 2\pi\sqrt\frac{I}{mgR}    .....................1

where, T is the time period

g is the acceleration due to gravity

I is the moment of inertia

Now,

Moment of inertia, I is given as:

I = \frac{5mR^{2}}{3}

on substituting the moment of inertia in the equation 1, we get

T = 2\pi\sqrt\frac{\frac{5mR^{2}}{3}}{mgR}

or

T = 2\pi\sqrt\frac{{5R}}{3g}

on substituting the valeus, we get

T = 2\pi\sqrt\frac{{5\times5.50\times10^{-2}}}{3\times9.8}

or

T = 0.607 seconds

Hence, the time period is 0.607 seconds

5 0
3 years ago
You leave a 3kW heater on in your room. You put it on at 8am and leave it on until 4pm. If a unit (1kWh) costs 12.5p, how much w
natali 33 [55]

Answer:

bpc

Explanation:

8 0
3 years ago
Two students stand poised to leap off a high dive structure into the swimming pool below. Student B is twice as massive as stude
iogann1982 [59]

Answer: option (D)

Explanation:

The potential energy of each of the students is given below as

P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.

The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as

P.E ( student B) =2mgh = 2(mgh)

Recall that the relationship between potential energy and work done is that

Work done = - (change in potential)

For student A, work done = - mgh

For student B, work done = - 2mgh

From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.

8 0
3 years ago
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