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3 years ago

True or false The momentum of a 100kg object traveling at 3 m/s is 300 N

Physics

1 answer:

melomori [17]3 years ago

5 0

Answer:

True

Explanation:

Momentum of an object can be defined as the product of its mass and velocity at which it is travelling. With that in mind, momentum = 3*100=300(kg⋅m/s).

One thing to note is the units mentioned. The SI unit of momentum is kg * m/s as it is the product of mass(kilograms) and velocity(meter per second) and not Newton.

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Two identical blocks are connected to opposite ends of a compressed spring. the blocks initially slide together on a frictionles

lana66690 [7]

Answer:

v to the right.

Explanation:

If there is no external force on the system, then the velocity of the center of mass is constant.

The initial velocity of center of mass is v to the right. Therefore, the velocity of the center of mass at any point is v to the right.

7 0

3 years ago

A 0.75 kg model car is moving west at a speed of 9.0 m/s when it collides head-on with a 2.00 kg model truck that is traveling e

Lyrx [107]

Answer:

2.5 m/s east

Explanation:

Let east be the positive direction for velocity.

The change in momentum of the 0.75 kg model car is ...

m1·v2 -m1·v1 = (0.75 kg)(11 m/s) -(0.75 kg)(-9 m/s)

= (0.75 kg)(20 m/s) = 15 kg·m/s

The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.

m2·v2 -m2·v1 = (2 kg)(v2 m/s) -(2 kg)(10 m/s) = 2(v2 -10) kg·m/s

The required relation is ...

15 kg·m/s = -2(v2 -10) kg·m/s

-7.5 = v2 -10 . . . . divide by -2

2.5 = v2 . . . . . . . add 10

The velocity of the model truck after the collision is 2.5 m/s east.

3 0

3 years ago

Amy needs 5.0 V for some integrated circuit experiments. She uses a 9.0 V battery and two resistors to make a voltage divider. O

just olya [345]

Answer:

The value of smaller resistor is 248 Ω.

Explanation:

Voltage divider circuit is used to convert a higher voltage to a smaller voltage with the help of resistors which are connected in parallel.

As shown in the circuit, Vs is the source voltage, R₁ and R₂ are the two resistors and V₀ is the output voltage.

Applying KVL in the circuit, the output voltage is given by :

$V_{0} = \frac{V_{s}R_{2} }{R_{1} + R_{2} }$

According to the problem, R₂ = 310Ω , V₀ = 5 V and Vs = 9 V. Substitute these values in the above equation.

$5 = \frac{9\times310 }{R_{1} + 310 }$

$R_{1}+310 = \frac{9\times310}{5}$

$R_{1} = 558 - 310$

R₁ = 248Ω

7 0

3 years ago

Find the acceleration of an object that has a mass of 6 kg, if it is acted upon by a net force of 42 N.

pychu [463]

Answer:

7 m/s²

Explanation:

The formula for force is:

$f= m*a$

We want to find acceleration, so we must rearrange the formula for $a$ . Divide both sides of the equation by $m$

$\frac{f}{m}=\frac{m*a}{m}$

$\frac{f}{m}=a$

Acceleration can be found by dividing the force by the mass.

The force is 42 newtons and the mass is 6 kilograms. A newton is equal to 1 kg * m/s², therefore the force is 42 kg* m/s².

$f= 42 kg*m/s^2\\m=6 kg$

Substitute the values into the formula.

$a=\frac{f}{m}$

$a=\frac{42 kg*m/s^2}{6kg}$

Divide. When we divide, the kg in the numerator and denominator will cancel each other out.

$a=\frac{42}{6}m/s^2$

$a= 7 m/s^2$

The acceleration of the object is 7 meters per square seconds.

7 0

3 years ago

A force of 3600 N is exerted on a piston that has an area of 0.030 m2. What force is exerted on a second piston that has an area

Airida [17]

For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
$p_1 = p_2$
which becomes
$\frac{F_1}{A_1}= \frac{F_2}{A_2}$
where
$F_1=3600 N$ is the force on the first piston
$A_1=0.030 m^2$ is the area of the first piston
$F_2$ is the force on the second piston
$A_2=0.015 m^2$ is the area of the second piston

If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
$F_2=F_1 \frac{A_2}{A_1}=(3600 N) \frac{0.015 m^2}{0.030 m^2}= 1800 N$

7 0

3 years ago

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