Question

Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constant acceleration throughout that time, find their acceleration in meters per second squared.

Answer 1

Answer:

$10.07m/s^2$

Explanation:

Information we have:

velocities:

initial velocity: $v_{i}=0mph$ (starts from rest)

final velocity: $v_{f}=50mph$

time:  $t=2.22s$

Since we need the answer in $m/s^2$, we nees to convert the speed to meters per second:

$v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s$

We find the acceleration with the following formula:

$a=\frac{v_{f}-v_{i}}{t}$

substituting the known values:

$a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2$

the acceleration is 10.07$m/s^2$

Answer 2

Answer:

The acceleration of the Cheetah is found to be 10.07 m/s²

Explanation:

We have the following data in this question:

Vf = Final Velocity of the Cheetah = 50 miles/hr

Vf = (50 miles/hr)(1 hr/ 3600 s)(1609.34 m/1 mile)

Vf = 22.35 m/s

Vi = Initial Speed of Cheetah = 0 m/s (Since, Cheetah starts from rest)

t = time interval passed = 2.22 s

So, in order to find the acceleration, we simply use the formula for acceleration, that is:

Acceleration = a = (Vf - Vi)/t

a = (22.35 m/s - 0 m/s)/2.22 s

a = 10.07 m/s²

The acceleration of the Cheetah is found to be 10.07 m/s²