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Gnom [1K]
3 years ago
13

What is the greatest common factor of 30 and 75? A. 25 B. 15 C. 5 D. 3

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0

Answer:

B).15

Step-by-step explanation:

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Have no idea helppppppppppp
mario62 [17]
Answer: choice A) 7017

==========================================================

Work Shown:

The first term is a_1 = 24 and we go up by 7 each time.
The common difference is d = 7

The nth term formula we'll use is
a_n = a_1 + (n-1)*d
a_n = 24 + (n-1)*7

----------

The 1000th term corresponds to n = 1000

Replace every n with 1000
Then use the order of operations (PEMDAS) to simplify

a_n = 24 + (n-1)*7
a_1000 = 24 + (1000-1)*7
a_1000 = 24 + (999)*7
a_1000 = 24 + 6993
a_1000 = 7017
3 0
4 years ago
The apothem is perpendicular to a side and forms two
Rus_ich [418]

Answer:

4

Step-by-step explanation:

6 0
3 years ago
My number 4752512944
choli [55]

Answer:

no thanks for your number

Step-by-step explanation:

Have a great day

7 0
3 years ago
Write a quadratic equation with integer coefficients and the given numbers as solutions.
adoni [48]

Answer:

1.)  f(x) = x*x - 7x + 10

2.) f(x) = x*x - 5x

3.) f(x) = 4*x*x - 5x - 6

4.) f(x) = 6*x*x -5x + 1

Step-by-step explanation:

1.)  2 and 5     (x -2)(x - 5) = f(x)  =  x*x - 7x + 10

2.)  0 and 5     f(x) = x*(x -5) =  x*x - 5x

3.) -3/4  and 2     (x + 3/4)(x -2) = x*x - (5/4) x - 3/2,

 need integers   f(x) = 4xx - 5x - 6

4.) 1/2  and 1/3    (x - 1/2)(x - 1/3) = f(x)

 x*x  - 1/3 x  - 1/2 x +  1/6  

xx  -  5/6  x  + 1/6

6 xx - 5x  + 1

4 0
4 years ago
An electronics store received two shipments of radios. Of the 250 radios in the first shipment, exactly 6% were damaged. In the
nataly862011 [7]

Answer:

Total number of not damaged = 451

C. 451

Step-by-step explanation:

In the first shipment, 6% of the 250 radios where damaged.

Number of damaged= 6/100 * 250

Number of damaged= 6*2.5

Number of damaged= 15 radios.

Number of not damaged= 250-15

Number of not damaged = 235 radios

In the second shipment, 4% of the radios were damaged

Let the number of second shipment= y

0.04 of y where damaged

Total number of radio damaged= 24

15 + 0.04y = 24

0.04y= 24-15

0.04y = 9

Y= 9/0.04

Y= 225

Number of radio in the second shipment= 225

Number of damaged in the second shipment= 0.04*225

Number of damaged in the second shipment= 9

Number of not damaged in the second shipment= 225-9

Number of damaged in the second shipment= 216

Total number of not damaged

= 235+216

= 451

Total number of not damaged= 451

7 0
3 years ago
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