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andrezito [222]
4 years ago
10

I need to know how to solve the following problem: 12x^-3 y^5 z^-7/ 4x^-2 y^4 z^6. Please include how you did it as well, thanks

!
Mathematics
2 answers:
natka813 [3]4 years ago
7 0
\bf \cfrac{12x^{-3}y^5z^{-7}}{4x^{-2}y^4z^6}\\\\
-----------------------------\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}\\ \quad \\a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}\\\\
-----------------------------\\\\

\bf thus
\\\\\\
\cfrac{12\frac{1}{x^3}y^5\frac{1}{z^7}}{4\frac{1}{x^2}y^4z^6}\implies 
\cfrac{\frac{12y^5}{x^3z^7}}{\frac{4y^4z^6}{x^2}}\implies \cfrac{12y^5}{x^3z^7}\times \cfrac{x^2}{4y^4z^6}\implies \cfrac{12y^5x^2}{4x^3y^4z^7z^6}
\\\\\\
\cfrac{12}{4}\cdot \cfrac{x^2}{x^3}\cdot \cfrac{y^5}{y^4}\cdot \cfrac{1}{z^7z^6}\implies 3\cdot \cfrac{1}{x}\cdot \cfrac{y}{1}\cdot \cfrac{1}{z^{7+6}}\implies \cfrac{3y}{xz^{13}}
Darina [25.2K]4 years ago
5 0
Do you have a picture with the problem and instructions? I can help but I need to see it
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Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

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The endpoints of (MP)are M(2,1) and P(12,6). If point K partitions (MP) in a ratio of MK:KP = 3:2, what are the coordinates of K
GREYUIT [131]

Answer:

K(8, 4)

Step-by-step explanation:

Given:

M(2, 1), P(12, 6)

MK:KP = 3:2

Required:

Coordinates of K

SOLUTION:

Coordinates of K can be determined using the formula below:

x = \frac{mx_2 + nx_1}{m + n}

y = \frac{my_2 + ny_1}{m + n}

Where,

M(2, 1) = (x_1, y_1)

P(12, 6) = (x_2, y_2)

m = 3, n = 2

Plug in the necessary values to find the coordinates of K:

x = \frac{mx_2 + nx_1}{m + n}

x = \frac{3(12) + 2(2)}{3 + 2}

x = \frac{36 + 4}{5}

x = \frac{40}{5}

x = 8

y = \frac{my_2 + ny_1}{m + n}

y = \frac{3(6) + 2(1)}{3 + 2}

y = \frac{18 + 2}{5}

y = \frac{20}{5}

y = 4

The coordinates of K = (8, 4)

3 0
3 years ago
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