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andrezito [222]
3 years ago
10

I need to know how to solve the following problem: 12x^-3 y^5 z^-7/ 4x^-2 y^4 z^6. Please include how you did it as well, thanks

!
Mathematics
2 answers:
natka813 [3]3 years ago
7 0
\bf \cfrac{12x^{-3}y^5z^{-7}}{4x^{-2}y^4z^6}\\\\
-----------------------------\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}\\ \quad \\a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}\\\\
-----------------------------\\\\

\bf thus
\\\\\\
\cfrac{12\frac{1}{x^3}y^5\frac{1}{z^7}}{4\frac{1}{x^2}y^4z^6}\implies 
\cfrac{\frac{12y^5}{x^3z^7}}{\frac{4y^4z^6}{x^2}}\implies \cfrac{12y^5}{x^3z^7}\times \cfrac{x^2}{4y^4z^6}\implies \cfrac{12y^5x^2}{4x^3y^4z^7z^6}
\\\\\\
\cfrac{12}{4}\cdot \cfrac{x^2}{x^3}\cdot \cfrac{y^5}{y^4}\cdot \cfrac{1}{z^7z^6}\implies 3\cdot \cfrac{1}{x}\cdot \cfrac{y}{1}\cdot \cfrac{1}{z^{7+6}}\implies \cfrac{3y}{xz^{13}}
Darina [25.2K]3 years ago
5 0
Do you have a picture with the problem and instructions? I can help but I need to see it
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Eddi Din [679]

Hello!

To find how much chocolate Adi and Suresh receives, you need to convert the percentage to a decimal, then you multiply that decimal by the total number of chocolates, which is 20.

To convert percentages to decimals, divide the percentage by 100, and remove the percentage.

60% / 100 = 0.60

20% / 100 = 0.20

Then, we multiply 0.60 and 0.20 by 20.

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6 0
3 years ago
A pet store sold 145 bags of beef flavored dog food and 263 bags of cheese-flavored dog food. How many bags of dog food were sol
Bingel [31]

Answer:

408 bags of dog foods were sold

Step-by-step explanation:

145 bags of beef flavored dog food

                           +

263 bags of cheese flavored dog food

                         =

408 bags of dog foods were sold.

8 0
3 years ago
Find x for equation 10 points
alexgriva [62]

Hi!

3x - 30 = x + 10

<h3>Solve by isolating x on one side. </h3><h3>Add 30 to both sides. </h3>

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<h3>Subtract x from both sides. </h3>

3x - x = x - x + 40

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<h3>Divide by 2 on both sides</h3>

2x/2 = 40/2

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-Peredhel

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