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Alecsey [184]
3 years ago
7

The HCF and LCM of two numbers x and 126 are 24 and 840 respectively. Find the value of x.

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

x=160

Step-by-step explanation:

x×126=24×840

x=\frac{24 \times840}{126} =160

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yawa3891 [41]
500=4πr^2. first divide 500 from four which will equal 125, then divide 125 with π and it will equal 39.788 . finally √39.788. the answer will be r=6.3 or 6
8 0
2 years ago
HELPPPPPPPP ASAPPPPP:
lina2011 [118]

Answer:

3

Step-by-step explanation:

4 0
2 years ago
Linear equations assignment:
Daniel [21]

Answer:

20 laps

Step-by-step explanation:

2 times = +1 dollars for Paula, +0.50 dollars for Jacki

Try multiplying it the least amount of times to Paula can have more and so 20 times and Paula will have 20 dollar sand Jacki will have 19.75, therefore she needs to do 20 laps.

6 0
2 years ago
A croissant shop produces two products: bear claws (B) and almond filled croissants (C). Each bear claw requires 6 oz of flour,
Kruka [31]

Answer:

letter A: B = 400; C = 1000; Max Z = $380

Step-by-step explanation:

bear claws (B) need 6 oz of flour (f), 1 oz of yeast (y), 2 ts of paste (p)

croissants (C) need 3 oz of flour (f), 1 oz of yeast (y), 4 ts of paste (p)

putting that information in equations, we have:

B = 6f + y + 2p

C = 3f + y + 4p

The total number of resources (R) are:

R = 6600f + 1400y + 4800p

Let's call M our total profit, "k1" the number of B produced and "k2" the number of C produced.

So, we can state that:

M = k1*0.2 + k2*0.3

The number of resources R2 will demand is calculated like this:

R2 = k1*B + k2*C = (6k1+3k2)f + (k1+k2)y + (2k1+4k2)p

using R2 and R, we can make some inequations:

6k1+3k2 <= 6600 -> 2k1+k2 <= 2200

k1+k2 <= 1400

2k1+4k2 <= 4800 -> k1+2k2 <= 2400

if we try to maximize k2 (as it worths more), we will have k1 = 0 and k2 = 1200 (limited by p), but looking at the resources R, we will still have resources to use (f and y). Looking at B and C expressions, we see that removing one C gives enough 'p' to make 2 B, which is a good trade (as 2B worths 0.4 cents, and 1C worths 0.3 cents). we have 200 'y' remaining, so doing this 200 times give us k1 = 400 and k2 = 1000, and the only resource remaining will be some of 'f'.

calculating the profit M, we have:

M = 400*0.2 + 1000*0.3 = 380$

the right answer is letter A.

3 0
3 years ago
Identify the x-intercept and y-intercept of the equation below.
Radda [10]

Answer:

x intercept at (7/3 , 0)

y intercept at (0,-3)

Step-by-step explanation:

9x-7y=21

we need to find x  and y intercepts

To find x intercept , plug in 0 for y

9x - 7(0) = 21

9x = 21

divide by 9 on both sides

x= 21/ 9 = 7/3

so x intercept at (7/3 , 0)

To find y intercept , plug in 0 for x

9(0) - 7(y) = 21

-7y = 21

divide by -7 on both sides

y= -3

so y intercept at (0,-3)

6 0
3 years ago
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