(x-8) ^ 2 = 121
(x-8) = + / - root (121)
x = 8 +/- root (121)
The solutions are:
x1 = 8 + root (121)
x2 = 8 - root (121)
2a ^ 2 = 8a-6
2a ^ 2-8a + 6 = 0
a ^ 2-4a + 3 = 0
(a-1) (a-3) = 0
The solutions are:
a1 = 1
a2 = 3
x ^ 2 + 12x + 36 = 4
x ^ 2 + 12x + 36-4 = 0
x ^ 2 + 12x + 32 = 0
(x + 4) (x + 8) = 0
The solutions are:
x1 = -8
x2 = -4
x ^ 2-x + 30 = 0
x = (- b +/- root (b ^ 2 - 4 * a * c)) / 2 * a
x = (- (- 1) +/- root ((- 1) ^ 2 - 4 * (1) * (30))) / 2 * (1)
x = (1 +/- root (1 - 120))) / 2
x = (1 +/- root (-119))) / 2
x = (1 +/- root (119) * i)) / 2
The solutions are:
x1 = (1 + root (119) * i)) / 2
x2 = (1 - root (119) * i)) / 2
So, when we're tasked with things like this, rewriting everything in terms of sine and cosine and combining fractions often trivializes things, so doing just that gives us:
So out expression is 1/cos(x).
Answer:
A = -12
B = -8
C = -4
Step-by-step explanation:
x = -2
A = -12
x = 0
B = -8
x = 2
C = -4
Hope this helps
Answer:
because they will taste bad because there burnt
Step-by-step explanation:
If you want to use integer tiles to find the product of 2(-5), think of it as you having 2 groups of 5 negative tiles, that is
-1 -1
-1 -1
-1 -1
-1 -1
-1 -1
Think of it as you having each of the -1 inside it's distinct tile. Now adding up these tiles you have -10.
Therefore 2(-5) is -10 using integer tiles.
If we are to use the number line, first draw your number line, then think of it as jumping twice while each jump is -5 big.
So the first jump from 0 will land on -5 and the second jump will land on -10 and that is the required answer using the number line.
