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uysha [10]
3 years ago
11

HELP!!! Please!!! I am struggling with this.

Mathematics
1 answer:
Anna007 [38]3 years ago
4 0
Bbbbhhhhhhhbbhhhbbhhgvb
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Not sure how to solve this :/
Sliva [168]

Answer:

SAME

Step-by-step explanation:

5 0
3 years ago
HELP ME WITH MATH EXIT TICKET PLEASE AND THANK YOU
juin [17]

Answer:

Don't know first cause I can't really see it but the second one is two times bigger

6 0
3 years ago
Subtraction and division are derived from which principal operations
JulsSmile [24]
There is no such thing as subtraction. Just something to think about :)

There are numbers and there is an operation called addition. Every number has an additive inverse, an opposite value.

Example: The opposite of 4 is -4.

When we do addition between numbers like 5 and the inverse of 2: 5 + -2 this is usually what we're thinking of when we talk about subtraction. We could write it as 5 - 2.

But anyway, to answer your question,

Subtraction and division are derived from the principle operations of ADDITION and MULTIPLICATION.
7 0
4 years ago
For a figure on a coordinate plane with the origin as the center of dilation, if (x, y) ⟶ (ax, ay) and (1.5, 2.0) ⟶ (6.0, 8.0),
Gnoma [55]
The correct answer to this question is 4.

In order to solve this problem, first make an image on your mind how the image is dilated.

The coordinate points at first is (1.5, 2.0). 
After dilation from the origin, the points became (6.0, 8.0)

Looking at it in fraction form, (new / old) we have
6.0 / 1.5 = 4.0
8.0 / 2.0 = 4.0

The quotient of each fraction yields to 4.0. This means that a = 4.

3 0
4 years ago
Find the zeroes of the following equation:
weqwewe [10]

Answer:  \bold{x=\dfrac{1\pm \sqrt5}{2}}

                both zeros are irrational numbers

<u>Step-by-step explanation:</u>

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}

7 0
3 years ago
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