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pochemuha
2 years ago
8

Can you help me solve this question ?

Mathematics
1 answer:
finlep [7]2 years ago
5 0

Answer:

Can u show the whole question pleade

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There are 7 women and 9 men if 2 are promoted what is the probability they are both men
Artist 52 [7]

Answer:

3/10

Step-by-step explanation:

Total number of employees = 7 + 9 = 16

Probability of a man being chosen first to be promoted = 9/16

Probability of the second choice is still a man for promotion = 8/15

Why 8/15?

The number of men left who are eligible for promotion after the 1st man was chosen for promotion is 9 - 1 = 8

The total number of people left after the 1st person is chosen for promotion that are eligible for promotion is 16 - 1 = 15

Hence Probability of choosing 2 men for promotion = 9/16 x 8/15 = 3/10

5 0
3 years ago
This table shows the size, in acres, of four large water parks.
Korvikt [17]
The answer is 65, hope this helps
6 0
3 years ago
Read 2 more answers
Can somebody answer this
Nimfa-mama [501]
A

Plug the values in and check


Mark brainliest please
4 0
2 years ago
Read 2 more answers
Kim’s hair grows a half inch per month. How many months will it take for her hair to grow 12 inches?
Contact [7]

Answer:

24 months

Step-by-step explanation:

Cross-multiply

0.5 inches -------------- 1 month

12 inches ---------------- x months

0.5/12 = 1/x ===> 0.5x = 12 ===> x = 12/0.5  ===> x = 24 months

3 0
3 years ago
A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us
Zanzabum

Answer:

Step-by-step explanation:

Hello!

The objective of the study is to determine whether the magnets are effective in treating pain. For these two independent groups of individuals with equal affections were randomly sampled, one was treated with magnets and the other group of individuals, call it control group, was treated with a placebo treatment.

The information for both samples is:

X₁: pain measurement using a visual analog scale after the individual received magnet treatments.

X₁~N(μ₁;σ₁²)

n₁= 20

X[bar]₁= 0.46

S₁= 0.93

X₂: pain measurement using a visual analog scale of an individual of the control groups.

X₂~N(μ₂;σ₂²)

n₂= 20

X[bar]₂= 0.41

S₂= 1.26

The claim is that the pain reductions of the control group have more variation than the pain reductions of the target group. If it's so then we could suspect that the population variance of the control group, σ₂², will be greater than the population variance of the magnet group, σ₁².

To test the relationship between these two population variances you have to conduct a variance ratio test using the Snedecors F statistic.

The hypotheses are:

H₀: σ₂² ≤ σ₁²

H₁: σ₂² > σ₁²

α: 0.05

F= (\frac{S_2^2}{S_1^2}) * (\frac{Sigma_2^2}{Sigma_1^2} )~~ F_{(n_2-1);(n_1-1)}

This hypothesis test is one-tailed to the right, there is only one critical value:

F_{(n_2-1);(n_1-1); 1 - \alpha } = F_{19;19; 0.95}= 2.17

The decision rule for the test is:

If F_{H_0} ≥ 2.17, then the decision is to reject the null hypothesis.

If F_{H_0} < 2.17, then the decision is to not reject the null hypothesis.

F_{H_0}= \frac{S_2^2}{S_1^2}*\frac{Sigma_2^2}{Sigma_1^2}  = \frac{(1.26)^2}{(0.93)^2} * 1

F_{H_0} = 1.835 = 1.84

Since the calculated value of F is less than the critical value, the decision is to reject the null hypothesis. So using a 5% significance level the decision is to not reject the null hypothesis, you can conclude that the population variance of the pain reduction of the control group is less or equal than the population variance of the pain reduction on individuals treated with magnets.

I hope it helps!

3 0
3 years ago
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