Two objects are held close together. When they are released, they move toward one another. Which conclusion is supported by this
2 answers:
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Answer:
The initial velocity of the gymnast is 8.5 m/s.
Explanation:
We can use the kinematic equation
to figure out the initial velocity of the gymnast.
Now, when the gymnast reaches the maximum height, the distance he has traveled is , and his velocity is zero; therefore
.
Thus, we have
Answer: 96 m/s
Explanation:
Given information
Acceleration of rocket = 24 m/s2
Distance travelled by rocket = 192 meters.
To be calculated
Velocity of rocket at 192 meters = ?
Using 2nd equation of motion, the difference of square of final and initial velocity is equal to the 2 times the product of acceleration and distance.
v2 – u2 = 2as
v2 – 0 = 2 * 24 * 192 (intial velocity is 0, so u = 0)
v2 = 9216
v =
v = 96 m/s