A charge of 6.4x 10^-7 c experiences an electric force of 1.8 x10^-1 N. What is the electric field strength ?
1 answer:
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Answer:
The mass of the Al-duckie should be 30 kg.
Explanation:
We will use the first law of thermodynamics:
ΔU = m·Cv·ΔT
Since the specific heat of water is 4.185 J(gºC), the change in the water's internal energy would be:
ΔU = 100 kg · 4.185 J(gºC) · (42ºC - 38ºC) = 1674 KJ
Given that no heat is lost, all the internal energy that the water loses while cooling down will transfer to the duckie. So, if the duckie has ΔU = 1674 KJ and its final temperature is the desired 38 ºC, we can calculate its mass using the first law again:
Answer:
a)
346.67 N/C, downward
b)
1.3 m
Explanation:
(a)
q = magnitude of charge on the particle = 1.95 x 10⁻⁹ C
r = distance of location from the charged particle = 0.225 m
E = magnitude of electric field at the location
Magnitude of electric field at the location is given as
Inserting the values
E = 346.67 N/C
a negative charge produce electric field towards itself.
Direction : downward
(b)
E = magnitude of electric field at the location = 10.5 N/C
r = distance of location from the charged particle = ?
q = magnitude of charge on the particle = 1.95 x 10⁻⁹ C
Magnitude of electric field at the location is given as
Inserting the values
r = 1.3 m