To calculate the number of shingles, we first calculate for the total area of the roof of Janice's house. From the figure, we can calculate the area of the two shapes: pyramid and a rectangular prism.
A(pyramid) = lw+l√[(w/2)²+h²]+w√[(l/2)²+h²]
A = 208 m²
A(prism) = 2(wl+hl+hw)
A = 293 m²
Total area = 501 m²
Number of shingles she needs = 501 m² / 2.25 m² =<span> 223</span><span>
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Answer:
Distributive property says that:
![a\cdot(b+c) = a\cdot b + a\cdot c](https://tex.z-dn.net/?f=a%5Ccdot%28b%2Bc%29%20%3D%20a%5Ccdot%20b%20%2B%20a%5Ccdot%20c)
Addition property of equality:
if x = y then x+z = y+z
Division property of equality:
if x = y then ![\frac{x}{z}=\frac{y}{z}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bz%7D%3D%5Cfrac%7By%7D%7Bz%7D)
As per the statement:
Given the equation: ![-3(x+2)=9](https://tex.z-dn.net/?f=-3%28x%2B2%29%3D9)
Tyra solve this equation as shown below:
1.
[Distributive property]
2.
[Addition property of equality]
3.
{Division property of equality]
Therefore, the property Tyra used in line 1 was : Distributive Property.
Answer:
how
Step-by-step explanation:
Answer:
d. none of these
Step-by-step explanation:
i think
Answer:
Option C .
Step-by-step explanation:
We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,
![\longrightarrow f(x) = x^2-12x +32](https://tex.z-dn.net/?f=%5Clongrightarrow%20f%28x%29%20%3D%20x%5E2-12x%20%2B32%20)
Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>
![\longrightarrow f(x) = 0\\](https://tex.z-dn.net/?f=%5Clongrightarrow%20f%28x%29%20%3D%200%5C%5C)
![\longrightarrow x^2-12x + 32=0](https://tex.z-dn.net/?f=%5Clongrightarrow%20x%5E2-12x%20%2B%2032%3D0)
Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>
![\longrightarrow x^2-8x - 4x +32=0\\](https://tex.z-dn.net/?f=%5Clongrightarrow%20x%5E2-8x%20-%204x%20%2B32%3D0%5C%5C)
![\longrightarrow x(x-8)-4(x-8)=0\\](https://tex.z-dn.net/?f=%5Clongrightarrow%20x%28x-8%29-4%28x-8%29%3D0%5C%5C)
![\longrightarrow (x-8)(x-4)=0\\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%28x-8%29%28x-4%29%3D0%5C%5C)
Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>
![\longrightarrow x - 8 = 0\\ \qquad x -4=0](https://tex.z-dn.net/?f=%5Clongrightarrow%20x%20-%208%20%3D%200%5C%5C%20%5Cqquad%20x%20-4%3D0%20)
![\longrightarrow x = 8 \qquad x = 4](https://tex.z-dn.net/?f=%5Clongrightarrow%20x%20%3D%208%20%5Cqquad%20x%20%3D%204%20)
![\longrightarrow \underline{\underline{\boldsymbol{ x = 8,4}}}](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Cunderline%7B%5Cunderline%7B%5Cboldsymbol%7B%20x%20%3D%208%2C4%7D%7D%7D)
<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>