I hate rounding.
Let's call the diagonal x. It's the hypotenuse of the right triangle whose legs are the rectangle sides.
According to the problem we have a length x-4 and a width x-5 and an area
82 = (x-4)(x-5)
82 = x^2 - 9x + 20
0 = x^2 - 9x - 62
That one doesn't seem to factor so we go to the quadratic formula

Only the positive value makes any sense for this problem, so we conclude

That's the exact answer. Did I mention I hate rounding? That's about
x = 13.6 meters
Answer: 13.6
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It's not clear to me this problem is consistent. By the Pythagorean Theorem the diagonal satisfies

which works out to

That's not consistent with the first answer; this problem really has no solution. Tell your teacher to get better material.
Answer:
C
Step-by-step explanation:
to factor x² - x - 2
consider the factors of the constant term which sum to give the coefficient of the x-term.
the factors are - 2 and + 1 since - 2 × 1 = - 2 and - 2 + 1 = - 1
x² - x - 2 = (x - 2)(x + 1), hence (x + 1) is a factor
Answer:
Idk fam
Step-by-step explanation:
......
Answer:
HOLA BB COM O ESTAS DIME QUE TE AYUDO BB
Step-by-step explanation:
Answer: (D) <em>bottom right graph</em>
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: f(x) = a(x - h)² + k, where
- (h, k) is the vertex
- |a| is the vertical stretch
- sign of "a" determines the direction of the parabola
Given g(x) = (x - 3)² - 5
- vertex (h, k) = (3, -5)
- vertical stretch |a| = 1
- sign of "a" is positive so parabola points up
The only graph that satisfies all of these conditions is the bottom right.