Answer:
the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg
Explanation:
Given that:
Initial Temperature 
= 15°C
Initial Pressure 
= 5 atm
Final Pressure 
= 1 atm
Data obtain from steam tables of saturated water at 15°C are as follows:
Specific volume v = 1.001 cm³/gm
The change in temperature = 2°C
Specific heat of water = 4.19 J/gm.K
volume expansivity β = 1.5 × 10⁻⁴ K⁻¹
The expression to determine the change in temperature can be given as :
Δ T = 0.093 K
Now; we can calculate the lost work bt the formula:
where ;
is the temperature of the surrounding. = 20°C = (20+273.15)K = 293.15 K
From above the change in entropy is:
Thus, the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg
Answer:
the curve will flatten due to the supply and demand theory.
Answer: Either your computer is malfunctioning or it is glitched and still thinks you only have 2. Also good job
Explanation: Leave a brainliest it helps
Answer:
water released through the bottom of the reservoir in 24 hrs is 1992 ha-cm
Explanation:
Given the data in the question;
A = 200 hectare = 2 × 10⁶ m²
water evaporated Ve = 2 × 10⁶ m² × 3 × 10⁻² = 60000 m³ { in 24 hrs }
Water added by storm in 24hrs Vi = 3 × 24 × 3600 = 259200 m³
now let water released be Vr
ΔV = V_ini - V_final = 0
Vi - Ve - Vr = 0
Vr = Vi - Ve
Vr = 259200 m³ - 60000 m³
Vr = 199200 m³ = 19920000 m² - cm
Vr = 1992 ha-cm
Therefore, water released through the bottom of the reservoir in 24 hrs is 1992 ha-cm
