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3 years ago

Systematic searching is a skill that takes ________ to master.

Engineering

2 answers:

bagirrra123 [75]3 years ago

7 0

Answer: B, repetitive practice! hope this helps. :)

Explanation:

inn [45]3 years ago

4 0

Answer: The answer is B

Explanation:

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Answer:

Explanation:

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3 years ago

The boy in the wagon begins throwing bricks out of the wagon to simulate rocket propulsion. The wagon begins at rest, and the bo

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3 years ago

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Third one
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3 years ago

Cho P1= XdaN, P2=3.X daN, P= 2.X (daN). a=1m, b=2m,MCN hình tròn d= (100+X)mm1/ Tính nội lực tại các mặt cắt cách ngàm 0,5m; 1m;

DaniilM [7]

Answer:

Please explain it in English so that i can help or you need someone else who can speak Vietnam

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2 years ago

(a) If 5 x 10^17 phosphorus atoms per cm3 are add to silicon as a substitutional impurity, determine the percentage of silicon a

Y_Kistochka [10]

Answer:

The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice = 0.001 %

The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice with boron atoms = 0.4 × $10^{-5}$ %

Explanation:

No. of phosphorus atoms = 5 × $10^{17} \ cm^{-3}$

The volume occupied by a single Si atom

$V_{si} = \frac{a^{3} }{8}$

$V_{si} = \frac{5.43^{3}(10^{-8} )^{3} }{8}$

$V_{si} =$ 2 × $10^{-23}$ $\frac{cm^{3} }{atom}$

$n_{si} = \frac{1}{V_{si} }$

$n_{si}$ = 5 × $10^{22}$ $\frac{atoms}{cm^{3} }$

$PCT = \frac{N_p}{N_{si}} 100$

Put the values in above equation we get

$PCT = \frac{5 (10^{17} )}{5 (10^{22}) } 100$

PCT = $10^{-3} = 0.001$ %

These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.

(b).

No. of boron atoms = 2 × $10^{15} \ cm^{-3}$

The volume occupied by a single Si atom

$V_{si} = \frac{a^{3} }{8}$

$V_{si} = \frac{5.43^{3}(10^{-8} )^{3} }{8}$

$V_{si} =$ 2 × $10^{-23}$ $\frac{cm^{3} }{atom}$

$n_{si} = \frac{1}{V_{si} }$

$n_{si}$ = 5 × $10^{22}$ $\frac{atoms}{cm^{3} }$

$PCT = \frac{N_p}{N_{si}} 100$

Put the values in above equation we get

$PCT = \frac{2 (10^{15} )}{5 (10^{22}) } 100$

PCT = 0.4 × $10^{-5}$ %

These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.

7 0

3 years ago