The mechanical energy of an object is a combination of its potential energy and its
1 answer:
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Answer:
Amount of air left in the cylinder=m=0.357 Kg
The amount of heat transfer=Q=0
Explanation:
Given
Initial pressure=P1=300 KPa
Initial volume=V1=0.2
Initial temperature=T=20 C
Final Volume==0.1
Using gas equation
m1==(300*0.2)/(.287*293)
m1=0.714 Kg
Similarly
m2=(P2*V2)/R*T2
m2=(300*0.1)/(0.287*293)
m2=0.357 Kg
Now calculate mass of air left,where me is the mass of air left.
me=m2-m1
me=0.715-0.357
mass of air left=me=0.357 Kg
To find heat transfer we need to apply energy balance equation.
Where me=m1-m2
And as the temperature remains constant,hence the enthalpy also remains constant.
h1=h2=he=h
Q=(me-(m1-m2))*h
me=m1-me
Thus heat transfer=Q=0
Answer:
drag coefficient for the parachute is Cd = 1.84177
Explanation:
given data
diameter = 8.0 m
average vertical speed = 3 m/s
total weight of load = 200 N
to find out
drag coefficient for the parachute
solution
we will apply here drag coefficient formula that is express as here
drag coefficient Cd = ......................1
here w is total load and A is area and v is speed
and here ρ = 1.22 kg/cu
put here value we get
Cd =
Cd = 1.84177
drag coefficient for the parachute is Cd = 1.84177