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olasank [31]
2 years ago
13

If I have a scaffold that is 83' tall, and the base of my scaffold is 5' wide least base dimension, then I am allowed to space m

y intermediate bracing supports every ____ feet maximum vertically with the lowest brace being no greater than _____ feet off the ground.
Engineering
1 answer:
Minchanka [31]2 years ago
8 0

In the scaffold, the intermediate bracing supports every 26 feet while the the lowest brace being no greater than 20 feet.

<h3>What is scaffold?</h3>

Scaffolding simply means a temporary structure that's used to support a work crew.

In this case, the height is 83 feet and the base width is 5 feet. The height to the width ratio will be:

= 83/5 = 16.6 > 4.

Therefore, the scaffold will be restrained. Lowest brace will be placed at 20 and intermediate support braces at 26 feet.

Learn more about scaffolding on:

brainly.com/question/20726451

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Homes may be heated by pumping hot water through radiators. What mass of water (in g) will provide the same amount of heat when
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Answer:

a mass of water required is mw= 1273.26 gr = 1.27376 Kg

Explanation:

Assuming that the steam also gives out latent heat, the heat provided should be same for cooling the hot water than cooling the steam and condense it completely:

Q = mw * cw * ΔTw = ms * cs * ΔTw + ms * L

where m = mass , c= specific heat , ΔT=temperature change, L = latent heat of condensation

therefore

mw = ( ms * cs * ΔTw + ms * L )/ (cw * ΔTw )

replacing values

mw = [182g * 2.078 J/g°C*(118°C-100°C) + 118 g * 2260 J/g ] /[4.187 J/g°C * (90.7°C-39.4°C)] = 1273.26 gr = 1.27376 Kg

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If my friend have the corona what do I do
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(E. Call the hospital to take them away
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Conduct online research and write a short report on the origin and evolution of the meter as a measurement standard. Discuss how
valina [46]

Answer:

People have come up with all sorts of inventive ways of measuring length. The most intuitive are right at our fingertips. That is, they are based upon the human body: the foot, the hand, the fingers or the length of an arm or a stride.

In ancient Mesopotamia and Egypt, one of the first standard measures of length used was the cubit. In Egypt, the royal cubit, which was used to build the most important structures, was based on the length of the pharaoh’s arm from elbow to the end of the middle finger plus the span of his hand. Because of its great importance, the royal cubit was standardized using rods made from granite. These granite cubits were further subdivided into shorter lengths reminiscent of centimeters and millimeters.

piece of black rock with white Egyptian markings

Fragment of a Cubit Measuring Rod

Credit: Gift of Dr. and Mrs. Thomas H. Foulds, 1925

Later length measurements used by the Romans (who had taken them from the Greeks, who had taken them from the Babylonians and Egyptians) and passed on into Europe generally were based on the length of the human foot or walking and multiples and subdivisions of that. For example, the pace—one left step plus one right step—is approximately a meter or yard. (On the other hand, the yard did not derive from a pace but from, among other things, the length of King Henry I of England’s outstretched arm.) Mille passus in Latin, or 1,000 paces, is where the English word “mile” comes from.

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Explanation:

is this short enough

5 0
2 years ago
Engineering Questions
valkas [14]
5 is the correct one to choose for this
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3 years ago
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A closed, rigid tank is lled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. The gas is he
sergejj [24]

Answer:

T₂ =93.77  °C

Explanation:

Initial temperature ,T₁ =27°C= 273 +27 = 300 K

We know that

Absolute pressure = Gauge pressure + Atmospheric pressure

Initial pressure ,P₁ = 300+1=301 kPa

Final pressure  ,P₂= 367+1 = 368  kPa

Lets take  temperature=T₂

We know that ,If the volume of the gas is constant ,then we can say that

\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}

{T_2}=T_1\times \dfrac{P_2}{P_1}

Now by putting the values in the above equation we get

{T_2}=300\times \dfrac{368}{301}\ K

The temperature in  °C

T₂ = 366.77 - 273  °C

T₂ =93.77  °C

8 0
3 years ago
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