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olasank [31]
2 years ago
13

If I have a scaffold that is 83' tall, and the base of my scaffold is 5' wide least base dimension, then I am allowed to space m

y intermediate bracing supports every ____ feet maximum vertically with the lowest brace being no greater than _____ feet off the ground.
Engineering
1 answer:
Minchanka [31]2 years ago
8 0

In the scaffold, the intermediate bracing supports every 26 feet while the the lowest brace being no greater than 20 feet.

<h3>What is scaffold?</h3>

Scaffolding simply means a temporary structure that's used to support a work crew.

In this case, the height is 83 feet and the base width is 5 feet. The height to the width ratio will be:

= 83/5 = 16.6 > 4.

Therefore, the scaffold will be restrained. Lowest brace will be placed at 20 and intermediate support braces at 26 feet.

Learn more about scaffolding on:

brainly.com/question/20726451

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Select four items that an industrial engineer must obtain in order to practice in the field.
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Answer:

Professional engineering license

Bachelor's degree

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2 years ago
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What is a p-n junction? Show by the diagram.
Natalija [7]

Answer:

The p-n junction is a region formed when a p -type semiconductor material is joined to an n-type semiconductor material

Explanation:

The p type semiconductor has holes as its majority charge carriers making it positively charged while the n –types has an overall negative charge. At the junction the holes move towards the electron until such a time when there is a balance in charges from both materials, which leads to the formation of the depletion zone as shown in the attachment below

                           

5 0
4 years ago
Firefighters are holding a nozzle at the end of a hose while trying to extinguish a fire. The nozzle exit diameter is 8 cm, and
ivanzaharov [21]

Question

Determine the average water exit velocity

Answer:

53.05 m/s

Explanation:

Given information

Volume flow rate, Q=16 m^{3}/min

Diameter d= 8cm= 0.08 m

Assumptions

  • The flow is jet flow hence momentum-flux correction factor is unity
  • Gravitational force is not considered
  • The flow is steady, frictionless and incompressible
  • Water is discharged to the atmosphere hence pressure is ignored

We know that Q=AV and making v the subject then

V=\frac {Q}{A} where V is the exit velocity and A is area

Area, A=\frac {\pi d^{2}{4} where d is the diameter

By substitution

V=\frac {16\times 4}{\pi 0.08^{2}}=3183.098862 m/min

To convert v to m/s from m/s, we simply divide it by 60 hence

V=\frac {3183.098862  m/min}{60 s}=53.0516477 m/s\approx 53.05 m/s

3 0
3 years ago
Direction: List down or enumerate the type of outlets you want to install on your dream house. Also indicate the quantity (in pi
Lorico [155]

Answer:

Apartment outlet 4pcs

Explanation:

6 0
3 years ago
A manometer containing a fluid with a density of 60 lbm/ft3 is attached to a tank filled with air. If the gage pressure of the a
8090 [49]

Answer:

The fluid level difference in the manometer arm = 22.56 ft.

Explanation:

Assumption: The fluid in the manometer is incompressible, that is, its density is constant.

The fluid level difference between the two arms of the manometer gives the gage pressure of the air in the tank.

And P(gage) = ρgh

ρ = density of the manometer fluid = 60 lbm/ft³

g = acceleration due to gravity = 32.2 ft/s²

ρg = 60 × 32.2 = 1932 lbm/ft²s²

ρg = 1932 lbm/ft²s² × 1lbf.s²/32.2lbm.ft = 60 lbf/ft³

h = fluid level difference between the two arms of the manometer = ?

P(gage) = 9.4 psig = 9.4 × 144 = 1353.6 lbf/ft²

1353.6 = ρg × h = 60 lbf/ft³ × h

h = 1353.6/60 = 22.56 ft

A diagrammatic representation of this setup is presented in the attached image.

Hope this helps!

5 0
4 years ago
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