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Anarel [89]
3 years ago
15

2(2x-3) + 3(x + 1) = 5x +2

Mathematics
2 answers:
Lerok [7]3 years ago
5 0
X=5/2 , remove parentheses , collect like terms, move terms , collect like terms and calculate the sum , then divide both sides by 2 , hope this helped broski
ANEK [815]3 years ago
5 0

2(2x-3) +3(x+1) = 5x+2

4x-6+3x+3 = 5x+2

7x-3 =5x+2

2x-3=2

2x=5

x = 5/2

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The ordered pair of y=2x+1 & y=-x+4
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I hope this helps you


-x+4=2x+1


4-1=2x+x


3=3x


x=1


y=-1+4


y=3
8 0
3 years ago
Two complex numbers have a sum of 14 and a product of 74. Write either of the two numbers.
IrinaVladis [17]

Answer:

Hello,

Step-by-step explanation:

The 2 numbers are roots of the equation:

U²-14U+74=0

Discriminant=14²-4*74=-100

<u>U=7-5i or U=7+5i</u>

3 0
3 years ago
Read 2 more answers
Michael borrows money from his uncle, who is charging him simple interest using the formula I = PRT. To figure out what the inte
katen-ka-za [31]

Answer:

c

Step-by-step explanation:

formula l=PRT

bring PT to right side we get

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or

R=l/PT

4 0
3 years ago
. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person
bulgar [2K]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or greater?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater

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3 years ago
Hey! i’ll give brainliest please help.
ruslelena [56]

Answer:

respect the traditions and beliefs

3 0
3 years ago
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