All categories

3 years ago

What are the measures of the other three angles formed by the intersection?

Mathematics

2 answers:

Umnica [9.8K]3 years ago

7 0

Could you resend the picture in the comments or maybe even write it out?
My screen is very blurry.

Phantasy [73]3 years ago

3 0

Angle 2 is 132 since it’s a vertical angle... i cant help you with the other 2 i’m sorry!!

You might be interested in

What are all the multiples of 5??

Setler [38]

5,10,15,20,25,30,35,40,45,50,55,60,65,70,75, 80,85,90,95,100 and so on

4 0

4 years ago

A data set consists of the following data points:

aleksley [76]

(3,5),
(5,8),
(6,13)
------
(14,26)/3

then use the point slope form of a line to find equation of line

 $y-y_1=m(x-x_1)
\\y - \frac{26}{3} = 2.5(x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} (x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{5}{2}\times\frac{14}{3}
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{35}{3}
\\6y-52=15x-70
\\15x-6y-18=0$

Find y-intercept for x = 0.

 $15x-6y-18=0
\\15\times0-6y-18=0
\\-6y=18
\\y=-3$

4 0

3 years ago

Which formula gives the x-coordinates of the maximum values for y = cos(x)?

solong [7]

We have been given a function $y=\cos(x)$ . We are asked to find the formula which gives the x-coordinates of the maximum values for given function.

We know that cosine function oscillates between $-1$ and 1 that is minimum value of cosine is $-1$ and maximum value is $1$ .

We also know that $\cos(0)=1$ and after period of cosine is $2\pi$ . This means after every $2\pi$ , we will get to $1$ .

So maximum of cosine is $2\pi n$ , where n is an integer.

Therefore, our required formula is $2\pi n$ , where, $n=0,\pm 1,\pm 2,\pm3,...$

7 0

3 years ago

Help me with this math

stellarik [79]

Answer:

(x+2)(x+5) or if you were looking for the x-intercepts they would be -5, and -2

7 0

3 years ago

Read 2 more answers

Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.

SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at $(0,1)$ .

The graph has an x-intercept at $(-7,0)$ .

Step-by-step explanation:

Given: The graph is $y=\sqrt[3]{x-1}+2$

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of $(-\infty, \infty)$ .

To find the y-intercept: To find the y-intercept, substitute $x=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}$

Thus, the y-intercept is $(0,1)$

To find the x-intercept: To find the x-intercept, substitute $y=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}$

Thus, the x-intercept is $(-7,0)$

8 0

3 years ago

Read 2 more answers