Answer:
4.7 × 10⁵J
Explanation:
E = I * a * t
80% = 0.80
25cm = 0.25m
52cm = 0.52m
0.90h = 3240s
E = (0.80)(1400)(0.25 * 0.52)(3240)
= 4.7 * 10⁵J
Explanation:
Thermal energy is basically the energy derived from heat when there is a temperature change in a body.
Kinetic energy is the energy due to the motion of a body.
Potential energy is the energy at rest or due to the position of a body.
- Thermal energy is highly related to kinetic and potential energy.
- Thermal energy is a type of kinetic energy because it causes the motion of the particles in a body.
- An increase in thermal energy gives the particles more energy to move and then, their kinetic energy increases.
- Kinetic energy is directly related to thermal energy.
- A low thermal energy increases the potential energy in a body.
- A body at rest will exert its maximum potential energy.
learn more:
Thermal energy brainly.com/question/914750
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B. Bacteria
C.Earthworms
D. Humus
@CristianoRonaldo
Answer:
t = 2s
Explanation:
When you're looking for instantaneous portions of a graph, of any sort really, it means you're observing a rate at a single point in time [or possibly some other variable]. It's sorta like a snapshot of a rate as opposed to an average rate over an interval. After choosing this rate we'll typically draw a straight, tangent line through it to indicate it's slope. (Tangent lines are just lines that only touch a single point on a graph or shape.)
Another thing to take note of are the values of the graph's major axes. The "y-axis" corresponds to velocity in meters per second, while the "x-axis" corresponds to time in seconds. Normally when relating the two we put "y" over the "x" and say that at any point there are "y[units]" per "x[units]". Though with instantaneous rates, we say the value of "x" is "1"; for reasons I can try to further explain later if you'd like.
With the above information in mind we can turn our attention to your graph. You're told to find the point on this graph where the instantaneous rate of acceleration is -2 m/s². The only place where the graph reflects an instantaneous rate of -2m/s² is at t = 2s. At t = 2, the rate comes out to (2[m/s]/1s), which simplifies to 2m/s². If you then draw the tangent line through the point, you'll find that the line is decreasing (going down from left to right) which means that the instantaneous rate is negative.
So at t = 2s, we have an instantaneous acceleration of -2m/s².
