<span>Unless the pig moves static friction acts on it once the pig starts moving kinetic friction comes in to play so when the pig is not moving=frictional force acting on it =normal force*co-efficient of static friction.</span>
Kinetic energy = (1/2) (mass) (speed)²
Since the 'speed' in the KE formula is squared, if the car's speed
increases by 5 times, its kinetic energy increases by (5²) = 25 times.
The loss of kinetic energy in a skid is just the wo0rk done by friction
between the tires and pavement. So the skid distance is proportional
to the initial kinetic energy, and the car must skid 25 times as far when
it enters the skid at the higher speed.
25 x 30m = 750 meters
Answer:
The acceleration of the car is 7.85 m/s²
Explanation:
Given;
vx(t)= (0.910m/s³)t², given time traveled by the car 't' = 5.0 s
⇒To determine the velocity for 5 seconds, we substitute in 5.0 s for t
vx(5)= (0.910m/s³)(5s)²
= (0.910m/s³)(25s²)
vx = 22.75 m/s
⇒To determine the acceleration of the car when vx=12.0m/s
Acceleration is change in velocity per unit time
when vx=12.0m/s, our new equation becomes; 12 = (0.910m/s³)t²
Solving for t: t² = 12/0.91
t² = 13.187
t = √13.187 = 3.63 s
Acceleration = Δv/Δt
Acceleration = 7.85 m/s²
Bigger change in velocity because the object is lighter than the object with more mass so it would move further (sorry it’s not a great explanation)
Well, the relationship between the net force and mass and acceleration of an object are directly related, as per the equation - Fnet = ma.
Thus the solution is A. As the net force of an object decreases, the object's acceleration also decreases, mass is kept constant.
