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liraira [26]
3 years ago
12

a stone is vertically thrown upward with the velocity of 72km/hr find the maximum height reached the height​

Physics
1 answer:
erik [133]3 years ago
3 0

Answer:

y = 20.38 [m]

Explanation:

In order to solve these problems, we must use the following kinematics equation.

v_{f} ^{2} =v_{i} ^{2}-(2*g*y)

where:

Vf = final velocity = 0

Vi = initial velocity = 72 [km/h]

g = gravity acceleration = 9.81 [m/s^2]

y = vertical elevation [m]

We need to convert [km/h] to [m/s]

72[\frac{km}{h}]*[\frac{1h}{3600s}]*[\frac{1000m}{1km} ] = 20 [m/s]

Note: the negative sign of the equation means that the acceleration acts in the opposite direction to the movement of the body. And the final speed is zero, because when the body reaches the maximum height, the Stone does not move its speed has been reduced to its entirety.

0 = (20)^2 - (2*9.81*y)

20^2 = 2*9.81*y

y = 20.38 [m]

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Answer:

Mechanical advantage = 2.875

Explanation:

Given:

A diagram is shown below for the above scenario.

Length of ramp (Effort arm) = 4.6 m

Height of truck bed ( Resistance length) = 1.6 m

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What is the mass moment of inertia of a 20kg sphere with a radius of 0.2m about a point on the sphere's perimeter
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Answer:

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a cart's initial velocity is +3.0 meters per second. What is its final velocity after accelerating at a rate of 1.5m/s2 for 8.0
Andreas93 [3]

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The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:

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Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

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