"It acts over a very small distance" would be the best answer as to a characteristic of the strong nuclear force, since its primary purpose is to bind the smallest particles together.
About 4.6 billion years ago
the answer is C the wave is moving horizontally as the particles of the rope move up and down.
Answer:
The frequency increases with a shorter horn <em>(Option B)</em>.
Explanation:
The length of the horn determines the distance along which the wave travels; simply called the wavelength. Therefore, a short horn tube will produce a short wavelength and vice versa.
Sound waves have various characteristics that define pitches in musical instruments and these characteristics are interdependent on each other.
in this case, the frequency and the frequency and the wavelength are related.
The relationship between the wavelength and its frequency is given as:
<em> </em><em>c = f λ </em><em> </em>
<em>where 'c' is the speed of sound through the instrument; 'f ' is the frequency and 'λ' is the wavelength.</em>
Let's assume that the speed at which the musician blows air into the mouthpiece remains constant, an increase in wavelength will cause a decrease in frequency. Conversely, as the tube of the horn becomes shorter the frequency increases.
To replace all forces on a pipe by the equivalent force
T= 8× 50 = 400lb.in
M = 16.30 = 480lb.in
F₂ = 50lb
To calculate the polar moment of inertia of shaft is
J = π/π²×(R⁴-r⁴)
= π²/2×(0.875⁴ - 0.750⁴)
= 0.423in.³
To calculate the moment of inertia
J= 1/2(J)
=1/2 (0.423)
=0.21188in.³
To calculate shear flow
Qy= 2/3(R³-r³)
= 2/3(0.875³- 0.750³)
= 0.16536in.³
To calculate the thickness of the shaft
t= R-r = 0.875 - 0.750 = 0.125 in.
The stress due to torsions is.
Tx = TR/J = 400 × 0.875/0.42376
=825. 9psi.
The stress due to bending
Qx =My/T = 480 × 0.875/0.2118
=1982.3psi
The stress due to transverse shear
Qx = VQ/I(2t)
=50 × 0.16536/0.2118× 0.250
=156.1psi