By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength
1 answer:
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Answer:
2m/s²
Explanation:
Given parameters:
Net force on the car = 2000N
Acceleration = 4m/s²
Unknown:
Acceleration of a car twice the mass = ?
Solution:
Let us first find the mass of the car;
Force = mass x acceleration
Mass =
Mass = = 500kg
Now,
whose mass is twice that of the car
Mass of the new car = 2 x 500 = 1000kg
So;
Acceleration =
Acceleration = = 2m/s²
Answer
given,
flow rate = p = 660 kg/m³
outer radius = 2.8 cm
P₁ - P₂ = 1.20 k Pa
inlet radius = 1.40 cm
using continuity equation
A₁ v₁ = A₂ v₂
π r₁² v₁ = π r₁² v₂
Applying Bernoulli's equation
v₂ = 1.97 m/s
b) fluid flow rate
Q = A₂ V₂
Q = π (0.014)² x 1.97
Q = 1.21 x 10⁻³ m³/s