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Ira Lisetskai [31]
2 years ago
8

By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength

Physics
1 answer:
djyliett [7]2 years ago
4 0
6 is the answer I remember the answer from when I took this and it was easy
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Briefly explain how an electric motor works.
NeTakaya
You put electricity<span> into it at one end and an </span>axle<span> (metal rod) rotates at the other end giving you the power to drive a machine of some kind. 


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3 0
3 years ago
Determine the kinetic energy of a 1000 kg roller coaster car that is moving with speed of 40.0 m/s​
ololo11 [35]

Answer:

KE=800,000

Explanation:

The formula for kinetic energy is KE=1/2mv^2 or Kinetic Energy= 0.5*mass*velocity^2

so 1000 is the mass and 40 is the velocity

KE=0.5*1000*40^2

KE=0.5*1,000*1,600

KE=800,000 Joules

8 0
3 years ago
Two objects, A and B, are in contact with one another. Initially, the temperature of A is 50 °C and the temperature of B is 100
V125BC [204]

Answer:

B

Explanation:

because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.

6 0
3 years ago
What does it mean to say something is proportional?
mamaluj [8]

Answer: When quantities have the same relative size. In other words they have the same ratio corresponding in size or amount to something else.

Explanation: Example: "A rope's length and weight are in proportion."

Example: "The punishment should be proportional to the crime"

4 0
3 years ago
Consider the following distribution of objects: a 2.00-kg object with its center of gravity at (0, 0) m, a 2.20-kg object at (0,
adelina 88 [10]

Answer:

body position 4 is (-1,133, -1.83)

Explanation:

The concept of center of gravity is of great importance since in this all external forces are considered applied, it is defined by

               x_cm = 1 /M   ∑ x_{i} m_{i}

               y_cm = 1 /M   ∑ y_{i} mi

Where M is the total mass of the body, mi is the mass of each element

give us the mass and position of this masses

body 1

m1 = 2.00 ka

x1 = 0 me

y1 = 0 me

body 2

m2 = 2.20 kg

x2 = 0m

y2 = 5 m

body 3

m3 = 3.4 kg

x3 = 2.00 m

y3 = 0

body 4

m4 = 6 kg

    x4=?

   y4=?

mass center position

x_cm = 0

y_cm = 0

let's apply to the equations of the initial part

X axis

    M = 2.00 + 2.20 + 3.40

    M = 7.6 kg

    0 = 1 / 7.6 (2 0 + 2.2 0 + 3.4 2 + 6 x4)

     x4 = -6.8 / 6

     x4 = -1,133 m

Axis y

    0 = 1 / 7.6 (2 0 + 2.20 5 +3.4 0 + 6 y4)

    y4 = -11/6

    y4 = -1.83 m

body position 4 is (-1,133, -1.83)

7 0
3 years ago
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