Answer:
20. ²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He
21. ⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca
Explanation:
20. ²⁴¹₉₅Am —> __ + ⁴₂He
Let ⁿₘX be the unknown.
Thus, the equation becomes:
²⁴¹₉₅Am —> ⁿₘX + ⁴₂He
Next, we shall determine n, m and X. This can be obtained as follow:
241 = n + 4
Collect like terms
n = 241 – 4
n = 237
95 = m + 2
Collect like terms
m = 95 – 2
m = 93
Thus,
ⁿₘX => ²³⁷₉₃X => ²³⁷₉₃Np
Therefore, the complete equation is:
²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He
21. __ —> ⁰₋₁β + ⁴²₂₀Ca
Let ʸₓZ be the unknown.
Thus, the equation becomes:
ʸₓZ —> ⁰₋₁β + ⁴²₂₀Ca
Next, we shall determine y, x and Z. This can be obtained as follow:
y = 0 + 42
y = 42
x = –1 + 20
x = 19
Thus,
ʸₓZ => ⁴²₁₉Z => ⁴²₁₉K
Therefore, the complete equation is:
⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca
