1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lubasha [3.4K]
3 years ago
15

5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats

to a temperature of 380 C in my lungs, what is the new volume of the gas?
Chemistry
1 answer:
ahrayia [7]3 years ago
8 0

Given :

If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs.

To Find :

The new volume of the gas.

Solution :

Since, their is no information about pressure, so we will assume that pressure is constant.

We know, relation between temperature and volume in constant pressure is :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Putting all given values in above equation, we get :

V_2 = \dfrac{V_1\times T_2}{T_1}\\\\V_2 = \dfrac{2.2\times (180+273)}{(380+273)}\\\\V_2 = 1.53 \ liters

Hence, this is the required solution.

You might be interested in
A 50.0 mg sample of iodine-131 was placed in a container 32.4 days ago. if its half-life is 8.1 days, how many milligrams of iod
sertanlavr [38]

3.124mg of I-131 is present after 32.4 days.

The 131 I isotope emits radiation and particles and has an 8-day half-life. Orally administered, it concentrates in the thyroid, where the thyroid gland is destroyed by the particles.

What is Half life?

The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.

Half of the iodine-131 will still be present after 8.1 days.

The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.

The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.

If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.

Learn more about the Half life of radioactie element with the help of the given link:

brainly.com/question/27891343

#SPJ4

7 0
1 year ago
Balance the chemical equations.<br> 1FeCl3 + KOH → Fe(OH)3 + KC1
wariber [46]

Answer:

FeCl3 + 3KOH → Fe(OH)3 + 3KCl

Explanation:

3 0
3 years ago
What is the practical use of scientific knowledge to solve everyday problems and improve lives?
Aleks04 [339]
A. Research is the answer
5 0
4 years ago
The heavier a gas molecule,
mr_godi [17]

Answer:

4

Explanation:

logic

3 0
3 years ago
How do you know that a bowling ball is a soild
julsineya [31]
It holds its own shape and it’s solid
4 0
3 years ago
Other questions:
  • What volume of 0.812 m ammonium sulfate contains 7.65 g of ammonium ion?
    8·1 answer
  • the solid above sink to the bottom when you put a container filled with it what does that tell you about density
    14·1 answer
  • Which element is likely to gain one electron when it combines chemically with another element? a potassium b krypton c gold d ch
    12·1 answer
  • You are part of a team of scientists and engineers in charge of launching a new spacecraft to Venus. What is one way in which kn
    10·2 answers
  • In the film, Lavoisier said that the mass gained by the pipe plus the mass of the collected gas "exactly" equaled the lost mass
    8·1 answer
  • Read the given expression.
    6·1 answer
  • What type of chemical bonds share electrons between atoms?
    8·1 answer
  • Which of the following types of radiation from the Sun has the longest wavelength?
    15·2 answers
  • What is a chemical change?
    6·1 answer
  • Balance each reaction and write its reaction quotient, Qc:(b) SF₆(g) + SO₃(g) → SO₂F₂(g)
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!