The main formulas are <span>pH=pKa + log(Base/Acid) and pKa = </span><span>-log(Ka)
so firstly, we must find the value of pKa,
Ka=6.37 x 10 ^-5, and then logKa= log (6.37 . 10^-5)= -9.66, so -logKa= +9.66=Ka
next let's find </span><span>log(Base/Acid)
for that the concentration of NaOH is [NaOH] = </span><span>500.0 x 0.110 / 500+535 =0.053M, the concentration of the Acid is [Acid] =535*0.25 / </span><span>500+535 =0.12M, so its difference is </span><span><span>[Acid]-</span>[NaOH] = 0.12-0.053=0.07
so pH=</span><span><span>pKa + log(Base/Acid)= 9.66 + log(0.053 / 0.07)= 9.66-0.36=9.29</span> </span>
so pH=9.29.
Answer:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Explanation:
In a <em>solubility table</em> you find:
- AgNO₃ (silver nitrate) is highly soluble
- KCl (potassium chloride) is soluble
- AgCl (silver chloride) is insoluble
- KNO₃ (potassium nitrate) is soluble
In a chemical equation the states of soluble compounds is identified as aqeous, using the letter "aq" in parenthesis, and the state of insoluble compounds is identified as solid, using "s" in parenthesis.
Then, the reaction showing the states of the reactants and products is:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Their prey would decrease
Answer:
D
Explanation:
The greater the distance apart, the lesser the gravitational force between the objects
Answer: A
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