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The molality of H₂SO₄ solution is 24.2 m.
<u>Explanation:</u>
We need to find the molality of sulfuric acid.
Mass of sulfuric acid = 785.6 g
Mass of water = 359 g
We have to find the moles of H₂SO₄ by using its mass and molar mass as,
Moles of H₂SO₄ =
= 8.7 moles
Mass of the solution in kg = = 0.359 kg
Molality =
=
= 24.2 m
So molality of the H₂SO₄ solution is 24.2 m.
Answer:
pH = 10.11
Explanation:
Hello there!
In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:
We can therefore set up the corresponding equilibrium expression:
Which can be written in terms of the reaction extent, :
Thus, by solving for we obtain:
However, since negative solutions are now allowed, we infer the correct is 0.0001285 M; thus, the pOH can be computed:
And finally the pH:
Best regards!