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Lisa [10]
3 years ago
8

Please if any one know any question help me please

Chemistry
1 answer:
pashok25 [27]3 years ago
7 0
Hhh hhbththrbvevevevevevr
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What is the pH of a solution that has a hydroxide ion concentration of 1.0×10−9 M?
bogdanovich [222]

Answer:

\boxed{\text{pH = 5.00}}

Explanation:

Step 1. Calculate the pOH

pOH =-log[OH⁻]

pOH =-log(1.0 × 10⁻⁹)

pOH = 9.00

Step 2. Calculate the pH

pH + pOH = 14.00

pH + 9.00 = 14.00

\boxed{\textbf{pH = 5.00}}

7 0
3 years ago
sample with masses 0.12g,1.8g, and 0.562g are mixed together the combind mass of the three samples expressed to the correct numb
allsm [11]

Answer:

2.5 g

Explanation:

Given data:

Masses of sample = 0.12 g, 1.8 g, 0.562 g

Combine mass of samples = ?

Solution:

When we add or subtract the values the number of significant figures after decimal in result must be equal to the given measurement having less number of decimal places.

0.12 g + 1.8 g + 0.562 g

2.482 g

In given three measurements 1.8 has less number of significant figure after decimal point which is only one digit. Thus the final value must contain one digit after decimal.

we will round of 2.482 g.

2.5 g

because the next digit after 4 is 8 that's why we will round 4 to 5.

3 0
3 years ago
What is Loschmidt’s number? How is it related to Avogadro’s number?
xxMikexx [17]
Loschmidt's constant is referred to as Avogadro's number (they are the same). Their values are 6.02 times 10 to the -34 power.
4 0
3 years ago
Can you guys help me on my science homework??​
natulia [17]

Answer:

1. B 2. D 3. Jon could test which animals like certain foods.

3 0
3 years ago
You are given 1.000 grams of hydrated Magnesium Sulfate (MgSO4*XH20). You place it into a crucible and heat it up past 100 C so
adelina 88 [10]

Answer:

MgSO4. 7H2O

There are seven water molecules attached to the hydrated salt.

Explanation:

From the equation;

Number of moles of hydrated salt = number of moles of anhydrous salt, we obtain:

Mass of hydrated salt/ molar mass of hydrated salt = mass of anhydrous salt/ molar mass of anhydrous salt

From the question;

Mass of hydrated salt = 1.000g

Molar mass of hydrated salt = 120.366 +18x gmol-1

Mass of anhydrous salt= 0.488g

Molar mass of anhydrous salt= 120.366 gmol-1

Substituting into the equation above;

1.000/120.366 +18x = 0.488/120.366

1.000/120.366 +18x = 0.004

1.000= 0.004 (120.366 +18x)

1.000= 0.48 + 0.072x

1.000 - 0.48 = 0.072x

0.52= 0.072x

x= 0.52/0.072

x=7

Therefore the hydrated salt is MgSO4. 7H2O

3 0
3 years ago
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