I think the correct answer from the choices listed above is option B. The formation of frost on a cold windowpane is an example of condensation. This process involves the phase change from the vapor phase to the liquid phase.
Answer:
18.2 g.
Explanation:
You need to first figure out how many moles of nitrogen gas and hydrogen (gas) you have. To do this, use the molar masses of nitrogen gas and hydrogen (gas) on the periodic table. You get the following:
0.535 g. N2 and 1.984 g. H2
Then find out which reactant is the limiting one. In this case, it's N2. The amount of ammonia, then, that would be produced is 2 times the amount of moles of N2. This gives you 1.07 mol, approximately. Then multiply this by the molar mass of ammonia to find your answer of 18.2 g.
#1 is 95L balanced . #2 is 55^3G balanced.
I think it would be solubility but I’m not sure
<span>Number of moles of Fe(CO)5 = mass/molar mass = (6.0 g) / (195.8955 g/mol) = 0.03 mol
Number of moles of PF3 = (4.0 g)/ (87.97 g/mol) = 0.0455 mol
Number of moles of H2 = (4.0 g) / (2.016 g/mol) = 1.984 mol
From the balanced equation
1 mol of Fe(CO)5 reacts with 2 mol of PF3 and 1 mol of H2
then 0.03 mol of Fe(CO)5 will need 0.03 (2/1) = 0.06 mol of PF3 and 0.03 mol of H2
Since we have less PF3 ( 0.0455 mol instead of 0.06 mol), that is the limiting agent</span>
